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natulia [17]
3 years ago
11

on a map a city block is a square with three of its vertices at (-4,1),(1,1),and(1,-4). what are the coordinates of the renaming

vertex
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0
(-4, -4) is the answer
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Solve using elimination 5x+7y=9 <br> 2x-3y=-37
uranmaximum [27]

Answer:

x = -8

y = 7

Step-by-step explanation:

5x + 7y = 9

2x - 3y = -37

1.) First, multiply each side to match either y-values or x-values. (In this example, we'll use match x-values)

10x + 14y = 18 (multiplied by 2)

10x - 15y = -185 (multiplied by 5)

2.) Then, subtract the entirety of one equation to isolate the y-value.

10x + 14y = 18

-10x + 15y = 185

3.) Add and subtract values and divide to find y.

29y = 203

y = 7

4.) Plug-in y to solve for x into one equation, or repeat steps 1-3.

15x + 21y = 27

14x - 21y = -259

29x = -232

x = -8

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Write a number with the digit<br> 8 in the tens place
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A number in the tens place 84
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Jim earns a regular hourly rate of $5 and a premium hourly rate of $6 He worked 45 Hours last week what is his gross pay
denpristay [2]
(40*5)+(5*6)=200+30 = 230

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Which expression is equal to: H • 3
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At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
3 years ago
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