Anybody got an answer ?

Mathematics

1 answer:

AfilCa [17]2 years ago

6 0

Sixty two is your answer you’re adding all the sides

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K=mv^2/2 solve for v

matrenka [14]

Answer: $v=\sqrt[]{\frac{2K}{m} }$

Step-by-step explanation:

$K=\frac{mv^2}{2}$

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

$2*K=\frac{mv^2}{2}*2$

$2K=mv^2$

Divide by m to isolate $v^2$ .

$\frac{2K}{m}=\frac{mv^2}{m}$

$\frac{2K}{m} =v^2$

To eliminate the square and isolate v, extract the square root.

$\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}$

$\sqrt[]{\frac{2K}{m} }=v$

let's rewrite it in a way that v is in the left side.

$v=\sqrt[]{\frac{2K}{m} }$

4 0

2 years ago

How do I work out -5(-8)

slava [35]

You have to simplify like this (-5)(-8)=40

5 0

3 years ago

Read 2 more answers

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kipiarov [429]

Answer: $x = (\frac{1}{4ab})^{2}$

Step-by-step explanation:

Given:

$4a\sqrt{x} = \frac{1}{b}$

To make $x$ the subject of the formula means that we want to make $x$ to stand alone , the first thing to do is to multiply through by 1/4a , that is