There is no right or wrong answer, your teacher wants you to support your own answer with points. As long as the reasons make logical sense you are fine.
I think they both have valid points. Their replies are both true, but from a buyer's perspective who would you purchase services from? You would get different answers depending on who you ask.
If you choose to go old school, obviously you get an actual photo that can be stored physically. This means it is a memory that can be preserved, and it might feel more nostalgic being able to touch the photo.
On the other hand, a digitally stored photo can be altered (photoshop), but it is forever as long as the internet still exists. A physical photo would fade with time, which doesn't happen with a digital photo.
It is definitely easier to argue that digital photography has more advantages (they do, it is why nobody uses film anymore)
Points you can consider:
Can be transferred to the other side of the world instantly
Ability to make copies and print as many photos as you want
Can be stored on cloud/devices and be like that forever
Compare them with film photography to give a more solid response.
Answer:
![X(t)= 24 cos (6.28 t +1.57)](https://tex.z-dn.net/?f=%20X%28t%29%3D%2024%20cos%20%286.28%20t%20%2B1.57%29)
And for this case we can write this expression like this:
![X(t) =A cos (wt +\phi)](https://tex.z-dn.net/?f=%20X%28t%29%20%3DA%20cos%20%28wt%20%2B%5Cphi%29)
The velocity would be given by the first derivate and we got:
![V(t) = -wA sin (wt +\phi)](https://tex.z-dn.net/?f=%20V%28t%29%20%3D%20-wA%20sin%20%28wt%20%2B%5Cphi%29)
And the maximum velocity would be:
![V_{max}= |6.28 *24| = 150.72 m/s](https://tex.z-dn.net/?f=V_%7Bmax%7D%3D%20%7C6.28%20%2A24%7C%20%3D%20150.72%20m%2Fs)
Explanation:
For this case we have the following function for the position:
![X(t)= 24 cos (6.28 t +1.57)](https://tex.z-dn.net/?f=%20X%28t%29%3D%2024%20cos%20%286.28%20t%20%2B1.57%29)
And for this case we can write this expression like this:
![X(t) =A cos (wt +\phi)](https://tex.z-dn.net/?f=%20X%28t%29%20%3DA%20cos%20%28wt%20%2B%5Cphi%29)
The velocity would be given by the first derivate and we got:
![V(t) = -wA sin (wt +\phi)](https://tex.z-dn.net/?f=%20V%28t%29%20%3D%20-wA%20sin%20%28wt%20%2B%5Cphi%29)
And the maximum velocity would be:
![V_{max}= |6.28 *24 |= 150.72 m/s](https://tex.z-dn.net/?f=V_%7Bmax%7D%3D%20%7C6.28%20%2A24%20%7C%3D%20150.72%20m%2Fs)
Required Heat = Q
Q = Mass * specific heat of water * change in temp.
Q = 5g * 1g/cal*degC * 20degC
Q = 100 cal of heat is required
To convert calories to Joules,
1 cal = 4.184 Joules
100cal = 418.4 J of heat is needed
By giving them an advice and by giving them encouraging and explaining the any theory
Answer:
3.7 m
Explanation:
We are given that
Mass of electron,m=![9.1\times 10^{-31} kg](https://tex.z-dn.net/?f=9.1%5Ctimes%2010%5E%7B-31%7D%20kg)
![Speed of electron,v=6.5\time 10^6 m/s](https://tex.z-dn.net/?f=Speed%20of%20electron%2Cv%3D6.5%5Ctime%2010%5E6%20m%2Fs)
Magnetic filed,B=![1.0\times 10^{-5} T](https://tex.z-dn.net/?f=1.0%5Ctimes%2010%5E%7B-5%7D%20T)
Charge on electron,q=![1.6\times 10^{-19} C](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-19%7D%20C)
We have to find the radius of circular path the electron follows.
We know that
Radius of circular path,r=![\frac{mv}{qB}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%7D%7BqB%7D)
Using the formula
![r=\frac{9.1\times 10^{-31}\times 6.5\times 10^6}{1.6\times 10^{-19}\times 1\times 10^{-5}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B9.1%5Ctimes%2010%5E%7B-31%7D%5Ctimes%206.5%5Ctimes%2010%5E6%7D%7B1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%201%5Ctimes%2010%5E%7B-5%7D%7D)
![r=3.7 m](https://tex.z-dn.net/?f=r%3D3.7%20m)
Hence, the radius of circular path followed by electron=3.7 m