Answer:
![\boxed {\boxed {\sf 4\ m/s^2}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%204%5C%20m%2Fs%5E2%7D%7D)
Explanation:
Acceleration is the rate of change of an object with respect to time. It is the change in velocity over the time.
![a= \frac{v_f-v_i}{t}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7Bv_f-v_i%7D%7Bt%7D)
The car starts at 10 meters per second and increases to 20 meters per second in 2.5 seconds.
= 20 m/s
= 10 m/s - t= 2.5 s
Substitute the values into the formula.
![a= \frac{ 20 \ m/s - 10 \ m/s}{2.5 \ s }](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7B%2020%20%5C%20m%2Fs%20-%2010%20%5C%20m%2Fs%7D%7B2.5%20%5C%20s%20%7D)
Solve the numerator.
![a= \frac{10 \ m/s}{2.5 \ s}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7B10%20%5C%20m%2Fs%7D%7B2.5%20%5C%20s%7D)
Divide.
![a= 4 \ m/s/s](https://tex.z-dn.net/?f=a%3D%204%20%5C%20m%2Fs%2Fs)
![a= 4\ m/s^2](https://tex.z-dn.net/?f=a%3D%204%5C%20m%2Fs%5E2)
The acceleration of the car is <u>4 meters per second squared.</u>
Answer: wavelength= 2.842m
Explanation:
wave speed C= frequency × wavelength
Wavelength= C/ frequency
= 2.998× 10exp8/ 105.5×10exp6Hz
Wavelength= 2.842m
Goodluck...
Answer:
Polarizing angle, ![\theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}](https://tex.z-dn.net/?f=%5Ctheta_%7BP%7D%20%3D%20tan%5E%7B-%201%7D%7B2.2%7D%20%3D%2065.56%5E%7B%5Ccirc%7D)
Given:
Critical angle, ![\theta_{cr} = 27^{\circ}](https://tex.z-dn.net/?f=%5Ctheta_%7Bcr%7D%20%3D%2027%5E%7B%5Ccirc%7D)
Solution:
Now, in Total Internal Reflection (TIR), the critical angle for cubic zirconia is given by:
(1)
where
= refractive index of zirconia
From eqn (1):
![\mu_{Z} = \frac{1}{sin\theta_{cr}}](https://tex.z-dn.net/?f=%5Cmu_%7BZ%7D%20%3D%20%5Cfrac%7B1%7D%7Bsin%5Ctheta_%7Bcr%7D%7D)
![\mu_{Z} = \frac{1}{sin(27^{\circ})} = 2.2](https://tex.z-dn.net/?f=%5Cmu_%7BZ%7D%20%3D%20%5Cfrac%7B1%7D%7Bsin%2827%5E%7B%5Ccirc%7D%29%7D%20%3D%202.2)
Now, the angle of polarization is given by:
tan![\theta_{P} = \mu_{Z}](https://tex.z-dn.net/?f=%5Ctheta_%7BP%7D%20%3D%20%5Cmu_%7BZ%7D)
Therefore,
![\theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}](https://tex.z-dn.net/?f=%5Ctheta_%7BP%7D%20%3D%20tan%5E%7B-%201%7D%7B2.2%7D%20%3D%2065.56%5E%7B%5Ccirc%7D)