1 year ago

Find the slope of the line that passes through the following points. (-2, 8) and (3, -2)

Mathematics

1 answer:

Elodia [21]1 year ago

3 0

Answer:

m=-2

Step-by-step explanation:

m=y2-y1/x2-x1

m=-2-8/3-(-2)

m=-2-8/3+2

m=-10/5

m=-2

You might be interested in

Solve the equation. 2(5c – 7) = 1

liq [111]

$\text{Hello there!}\\\\\text{Solve for c:}\\\\2(5c -7) = 1\\\\\text{First, distribute the 2}\\\\10c-14=1\\\\\text{Add 14 to both sides}\\\\10c=15\\\\\text{Divide both sides by 10}\\\\c=1.5\\\\\boxed{\text{Answer: c = 1.5 or 3/2}}$

8 0

3 years ago

Please write the solution

GrogVix [38]

Answer:

Step-by-step explanation:

that is the answer to the question above

3 0

1 year ago

Ex 2.8<br> 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1

harkovskaia [24]

$y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\
y''(0)=20\cdot0^3=0$

The value of the second derivative for $x=0$ is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of $5x^4$ is always positive for $x\in\mathbb{R}\setminus \{0\}$ . That means at $x=0$ there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval $[-2,1]$ .
The function $y$ is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

$y_{max}=y(1)=1^5-3=-2$

4 0

2 years ago

Choose the equation that best represents the general form of the following expression. x^2/2 = 7x. - x2 + 14x + 0, x2 + 14x = 0,

kogti [31]

Cross multiplying we get
x^2 = 2*7x
x^2 = 14x
x^2 - 14x = 0 is the answer

6 0

2 years ago

Read 2 more answers

On average 14.1% of welds performed by a particular welder are defective. if, in one day, the welder creates three welds. what i

Salsk061 [2.6K]

The answer is =cube of 0.859

7 0