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sergey [27]
2 years ago
8

What does the product of the two circled numbers represent? ​

Mathematics
2 answers:
Stella [2.4K]2 years ago
8 0

Answer:

18

Step-by-step explanation:

<u>Product</u> is another word for multiplication, and 2 * 9 = 18.

Hope this helps! :D

~Kk

Gekata [30.6K]2 years ago
6 0

The answer you are looking for is Letter A., 18.

Clearly, the two circled numbers are 9 and 2, and since there is a multiplication sign, we know that we must multiply these two terms to find the final product and answer for this problem.

Since 9×2=18, the product of the two circled numbers represents 18, Letter A..

So, therefore, the final answer to this problem is Letter A., 18.

Hope this helped answer your question for you. Good day to you.

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There are 5 chemistry, 6 physics, and 7 math teachers in a school. if 3 teachers are selected randomly, find the probability tha
mrs_skeptik [129]
77.2%

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6 0
2 years ago
:&gt;
nevsk [136]

#Personal computer:-

  • Total=480

Percent

\\ \bull\sf\dashrightarrow \dfrac{480}{1500}\times 100

\\ \bull\sf\dashrightarrow 32\%

#Pacemaker:-

\\ \bull\sf\dashrightarrow 0.26(1500)

\\ \bull\sf\dashrightarrow 390

#Wireless communication:-

\\ \bull\sf\dashrightarrow 0.18(1500)

\\ \bull\sf\dashrightarrow 270

#Television:-

Percent

\\ \bull\sf\dashrightarrow \dfrac{150}{1500}\times 100

\\ \bull\sf\dashrightarrow 10\%

#Others

  • 100-(10+18+26+32)=100-86=14%

\\ \bull\sf\dashrightarrow 0.14(1500)

\\ \bull\sf\dashrightarrow 225

4 0
2 years ago
Read 2 more answers
Which of the following cannt be solved using the quadratic formula?
Katarina [22]

Answer:

C. 2x+3=0 cannot be solved using the quadratic formula.

Step-by-step explanation:

8 0
3 years ago
If you can answer this you are a star , plzz i need help
BlackZzzverrR [31]

Answer:

\left[\begin{array}{ccc}9\\10\\\end{array}\right]

Step-by-step explanation:

Multiply the components of A by 3 then add corresponding components of

3a + b

3\left[\begin{array}{ccc}2\\4\\\end{array}\right] + \left[\begin{array}{ccc}3\\-2\\\end{array}\right]

= \left[\begin{array}{ccc}6\\12\\\end{array}\right] + \left[\begin{array}{ccc}3\\-2\\\end{array}\right]

= \left[\begin{array}{ccc}6+3\\12-2\\\end{array}\right]

= \left[\begin{array}{ccc}9\\10\\\end{array}\right]

8 0
2 years ago
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