Answer:
a) 229 and 305 days
b) 229 days or less
c) 305 days or more
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 267
Standard deviation = 19
(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days
By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.
So
267 - 2*19 = 229 days
to
267 + 2*19 = 305 days
(b) How short are the shortest 2.5% of all pregnancies?______days or less
95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So
267 - 2*19 = 229 days
c) How long do the longest 2.5% of pregnancies last?________days or more
Explanation in b)
267 + 2*19 = 305 days
Answer:
A
Step-by-step explanation:
yiu have to rotate it in order to make that
The question is asking for you to plug in each number in the brackets into x and solve for y, or f(x), g(x), etc. I will do no. 19 as an example:
f(x) = -3x + 1
This problem has the domains -2, -1, and 0. First, we'll start with -2:
f(x) = -3(-2) + 1
f(x) = 6 + 1
f(x) = 7
Now -1:
f(x) = -3(-1) + 1
f(x) = 3 + 1
f(x) = 4
Lastly, 0:
f(x) = -3(0) + 1
f(x) = 0 + 1
f(x) = 1
For question 23, we can use the distance formula, which is ratextime. The domain in this case is time (t). You can set up a function like this: d(t) = 60t
Answer:
Step-by-step explanation:
4b - 6d = 4*7 - 6*3
= 28 - 18
= 10
Answer:
Step-by-step explanation:
138/8 = 17.25
