This is a long and tedious process but basically what you want to do is draw little rectangles to approximate the area. In this case what the problem wants you to do is
f(0)*2(length times width)+f(2)*2+2(4)*2+f(6)*2+f(8)*2+f(10)*2+f(12)*2+... +f(20)*2+f(22)*2=
(f(0)+f(2)+f(4)+f(6)+f(8)+f(10)+f(12)+f(14)+f(16)+f(18)+f(20)+f(22))*2=
approximately, I don't know how specific you're teacher wants them but Im putting down f(x) in integers for the sake of simplicity:
(9+10+11+12+15+18+21+26+27+26+17+13)*2=410
Answer:
Step-by-step explanation:
Start by moving the 3 to the other side of the equals sign to get
so with that replacement:
By the Zero Product Property,
or
Yes these are both the same, so we only need one of them. Once we find the angle, they are both the same, so we only need one of these equations.
If
, take the inverse tangent of both sides to give you:
and
so
Tangent increases in increments of pi or 180, so the other angle within the given interval is 35.8 + 180 = 215.8
Answer:
c
Step-by-step explanation:
I attached a desmos graph so you could get a better understanding but it's right 1, down 2
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Define x :
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Let the number be x.
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Construct Equation:
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x ÷ (-10) = -30
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Multiply for (-10) on both sides:
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x = (-30) x (-10) = 300
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Answer: x = 300
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