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AleksAgata [21]
3 years ago
6

Please help me out!!!!!!!!!!!!!

Mathematics
1 answer:
Olenka [21]3 years ago
6 0
The equation given means it wants you to solve in the format y=mx+b, for a line. You can also know that by comparing the difference between each y-coordinates.

m is the slope. b is the y intercept (where x is zero, which is on the table).

The answer is y=6x-2

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Fourteen is 6 less a number (n). Which equation shows this relationship?
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Answer:

14+6=n=20

Step-by-step explanation:n=20

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Find the slope of each line.<br> 1) y=− x−5<br> 2) y=− x−1
poizon [28]

1) slope = -1

2) slope = -1

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4 years ago
1. In a 30-60-90 triangle, the length of the hypotenuse is 6. What is the length of the shortest
PIT_PIT [208]

Answer:

b. 3

Step-by-step explanation:

In a 30°-60°-90° triangle, the short side is ½ the hypotenuse [the long side is double the short side].

30°-60°-90° Triangles

x√3 → long side

x → short side

2x → hypotenuse

45°-45°-90° Triangles

x → two legs

x√2 → hypotenuse

I am joyous to assist you anytime.

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3 years ago
45 pts! which explicit function defines this geometric sequences?<br> 3, 1, 1/3, 1/9...
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Answer:

c

Step-by-step explanation:

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3 years ago
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Please help solve this system of equations
stepan [7]

Make a substitution:

\begin{cases}u=2x+y\\v=2x-y\end{cases}

Then the system becomes

\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}

Simplifying the equations gives

\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}

which is to say,

\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}

\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81

\implies\dfrac uv=\pm27

\implies u=\pm27v

Substituting this into the new system gives

\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1

\implies u=\pm27

Then

\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13

(meaning two solutions are (7, 13) and (-7, -13))

8 0
3 years ago
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