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GREYUIT [131]
3 years ago
12

For f (x) = x2 - 5, find f (x) when x = 0 and when x = 3 f (0) = f (3) =

Mathematics
1 answer:
Bas_tet [7]3 years ago
7 0

Answer:

1 minus 1 is 0

Step-by-step explanation:

1-1 equals 0

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Which ordered pair could replace the missing value and create a
Usimov [2.4K]

Answer:

C

Step-by-step explanation:

The same x value cannot be used more than once or it isn't a function.

8 0
3 years ago
Read 2 more answers
Can some one please help me
Nady [450]
40 = 1 x 2 x 2 x 2 x 5
8 0
3 years ago
Solve the problem.<br> Find the radius of a circle that has a circumference of 942 meters.<br> m
Montano1993 [528]
Circumference is equal to diameter multiplied by pi. C=d X pi. To find the radius we need to rearrange this equation. We know what pi and the circumference are, so to find diameter we do circumference divided by pi. D=c/pi. 942/pi = 299.85. This gives us the diameter, for the radius simply divide by 2 which is 149.92 :)
5 0
3 years ago
The line AB has the midpoint of (2,5) A has coordinates (1,7) find the coordinates of B
Pavel [41]

Answer:

Point B is at (3,3)

Step-by-step explanation:

the mid point is (2,5) and A is at (1,7)

first find the slope:

y1 - y2/x1 - x2

7 - 5/1 - 2

2/-1

-2/1

then go down 2 units and right 1 unit from (2,5):

(2 + 1, 5 - 2) => (3,3)

6 0
3 years ago
What is the square root of 5 divided by the square root of 15 and simplify and in fraction form​
ozzi

Answer:

\sqrt{\frac{1}{3} }

or

\frac{\sqrt{3} }{3}

Step-by-step explanation:

The expression \frac{\sqrt{5} }{\sqrt{15} } can be simplified by first writing the fraction under one single radical instead of two.

\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }

5/15 simplifies because both share the same factor 5.

It becomes \sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }

This can simplify further by breaking apart the radical.

\sqrt{\frac{1}{3} }  = \frac{\sqrt{1} }{\sqrt{3} }  = \frac{1}{\sqrt{3} }

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} }  =\frac{\sqrt{3} }{3}

4 0
3 years ago
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