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Alexxandr [17]
3 years ago
8

D. Is no solution please help

Mathematics
2 answers:
dangina [55]3 years ago
5 0

Answer:

B

Step-by-step explanation:

I can't really see the problem, however I believe B is the only one that shows an infinite number of solutions.

tatiyna3 years ago
5 0

Answer:

B

Step-by-step explanation:

It is too blurry BTW but B is correct

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Meghan is attending a college where tuition is $6,600 per year. She received a $2,000 grant and her parents will give her anothe
n200080 [17]

ANSWER:

Total fee per year = $6,600.

In which she have,

  • $2,000 + $1,500
  • $3,500

Now, we need to subtract it from total fee to get the remaining demand.

So, $6,600 - $3,500

  • $3,100

Hence, Meghan will have to earn __$3,100__ to pay for the first year tuition.

4 0
3 years ago
Write each ratio as a fraction in lowest terms. 8 to 9​
3241004551 [841]

Answer:

8/17 and 9/17

Step-by-step explanation:

8:9

both add up to 17

so it can be 8/17 or 9 but it cannot be simplified unless if you want them both as a mixed number which is

8/17 as a mixed number is 2 1/17

9/17 as a mixed number is 1 8/17

8 0
3 years ago
Please solve this worksheet. (Factoring trinomials)
mash [69]

Answer:

where's the worksheet

Step-by-step explanation:

6 0
3 years ago
Polygon ABCD is plotted on a coordinate plane and then rotated 90° clockwise about point C to form polygon A′B′C′D′. Match each
horrorfan [7]

The vertices of ABCD after 90 degrees clockwise rotation about point C are: A' (0,6), B' (3,7), C' (4,6) and D' (4,3)

<h3>How to match the vertices of the polygon?</h3>

The image of the polygon ABCD is not given; however, the question can still be answered because the coordinates are known.

The vertices of polygon ABCD are given as:

A = (4, 6)

B = (5, 3)

C = (4, 2)

D = (1, 2)

The rule of rotation about point C is:

(x,y) = (a + b - y, x + b - a)

Where:

(a, b) = (4, 2) --- the point of rotation.

So, we have:

(x,y) = (4 + 2 - y, x + 4 - 2)

(x,y) = (6 - y, x + 2)

The above means that:

A' = (6 - 6, 4 + 2) = (0,6)

B' = (6 - 3, 5 + 2) = (3,7)

C' = (6 - 2, 4 + 2) = (4,6)

D' = (6 - 2, 1 + 2) = (4,3)

Hence, the image of the rotation and their vertices (i.e. coordinates) are:

A' = (0,6)

B' =  (3,7)

C' = (4,6)

D' =  (4,3)

Read more about rotation at:

brainly.com/question/4289712

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8 0
2 years ago
Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:
kondaur [170]
\text{Proof by induction:}
\text{Test that the statement holds or n = 1}

LHS = (3 - 2)^{2} = 1
RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS
\text{Thus, the statement holds for the base case.}

\text{Assume the statement holds for some arbitrary term, n= k}
1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}

\text{Prove it is true for n = k + 1}
RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}

LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}
= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}
= \frac{k(6k^{2} + 15k + 11) + 2}{}
= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}
= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}
= RHS

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.
3 0
3 years ago
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