Question

Two number cubes are rolled sequentially. What is the probability that the first number cube shows a Four and the second number cube shows an odd number?

Answer 1

Answer:

$\frac{1}{12}$

Step-by-step explanation:

This is an independent event probability problem , that is the first event does not affect the occurrence of the second event.

The sample space of the first die is S1= {1,2,3,4,5,6}

The sample space of the second die is S2= {1,2,3,4,5,6}

1. the probability that the first number cube shows a Four  pr (4)= $\frac{1}{6}$

2. the probability that the second number cube shows an odd number=

odd numbers in the sample space are 1,3,5= 3

pr(odd) $= \frac{3}{6} = \frac{1}{2}$

For the two event to happen the probability is = $\frac{1}{6}*\frac{1}{2}=\frac{1}{12}$