Answer:
6x + 2 ( x - 4) = 8 + 4 ( x + 2)
6x + 2x - 8 = 8 + 4x + 8
<em><u>Arranging</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>terms</u></em><em><u> </u></em>
6x + 2x - 4x = 8 +8 - 8
8x - 4x = 8
4x = 8
x = 8/4
x = 2
Answer:
1) 8 : 343
2) 42.875 or 42 ⅞
3) 4 : 49
4) 16ft²
Step-by-step explanation:
Volume of cube: s³
Surface area of cube: 6s²
_____________________
32ft^3 and 1372ft^3 →
32 : 1372 = 8 : 343
343 / 8 = 42 ⅞ = 42.875
s³ → 6s²
s³ = 8, s = 2, s² = 4.
s³ = 343, s = 7, s² = 49.
These are proportional so it is already in the simplest ratio so it is not necessary to multiply by 6.
s³ → 8 : 343
6s² → 4 : 49
(4 / 49) × 196ft² = 16ft²
Answer:
On Graph B, at 0 hours, the graph will be at 0 feet.
Then, the graph will increase until 1 hour, when the submarine reaches its deepest point.
At 1 hour, the height of Graph B will be 4000 feet.
Step-by-step explanation:
8. complementary angles = 90°
3x+3+10x-4 = 90
13x-1 = 90
13x = 91
so x = 91/13= 7
then K = 3(7)+3 = 24°
so L = 10(7)-4 = 70-4 = 66°
9. P is three less than twice of Q
so P = 2Q-3
supplementary angles = 180°
P+Q = 180
(2Q-3)+Q = 180
3Q-3 = 180
3Q = 183
so Q = 183/3 = 61°
then P= 2(61)-3 = 122-3 = 119°
10. B is two more than three times of C so B= 3C+2
complementary angles = 90°
B+C= 90
(3C+2)+C=90
4C+2=90
4C= 88
so C= 22°
then B = 3(22)+2= 66+2 = 68°
Answer:
Calculating the distance travelled
Calculate the total distance travelled by the object - its motion is represented by the velocity-time graph below.
Here, the distance travelled can be found by calculating the total area of the shaded sections below the line.
½ × base × height.
½ × 6 × 2 = 12 m 2
(10 – 6) × 2 = 8 m 2
