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Inessa [10]
3 years ago
12

In a fraction the denominator is 5 more than numerator.When 3 is added to the numerator and 1 is added to the denominator the si

mplest form of the fraction is 2/3. Find the original fraction.​
Mathematics
2 answers:
Leno4ka [110]3 years ago
6 0
<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ The original fraction can be written as:

x/x + 5

This is the information we have:

x + 3/x + 6 = 2/3

Cross multiply them:

3x + 9 = 2x + 12

Subtract 2x from both sides:

x + 9 = 8

Subtract 9 from both sides:

x = 3

The original fraction was 3/8

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Marysya12 [62]3 years ago
4 0

Answer:

<u> 3/8.</u>

Step-by-step explanation:

Let the original fraction be x / (x + 5).

Then (x + 3) /  (x + 5 + 1)  = 2/3

x + 3 / x + 6 = 2 / 3

Cross multiply:

3(x + 3) = 2(x + 6)

3x + 9 = 2x + 12

x = 12 - 9 = 3

The original fraction is 3 / (3 + 5)

=<u> 3/8.</u>

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An economist is interested in studying the spending habits of consumers in a particular region. The population standard deviatio
Lena [83]

Answer:

The  width is  w = \$ 729.7

Step-by-step explanation:

From the question we are told that

   The population standard deviation is  \sigma =  \% 1,000

    The  sample size is  n  = 50

    The sample mean  is  \= x  =  \$ 15,000

Given that the confidence level is  99% then the level of significance is mathematically represented as  

               \alpha  =  100 - 99

=>            \alpha  =  1\%

=>             \alpha  = 0.01

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is

             Z_{\frac{\alpha }{2} } = Z_{\frac{0.01 }{2} } =  2.58

Generally margin of error is mathematically represented as

             E =  Z_{\frac{\alpha }{2} *  \frac{\sigma }{\sqrt{n} }

substituting values

              E = 2.58 *  \frac{1000 }{\sqrt{50} }

              E = 2.58 *  \frac{1000 }{\sqrt{50} }

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5 0
2 years ago
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
The sum of three consecutive odd integers is 18 less than five times the middle number fimd the three integers
ycow [4]

Answer:

7, 9, 11

Step-by-step explanation:

x+x+2+x+4=5(x+2)-18

3x+6=5x+10-18

3x+6=5x+-8

3x=5x+-14

-2x=-14

x=7

7 0
3 years ago
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