Answer:
"To the nearest year, it would be about 9 years"
Step-by-step explanation:
11c)
This is compound growth problem. It goes by the formula:
Where
F is the future amount
P is the present (initial) amount
r is the rate of growth, in decimal
t is the time in years
Given,
P = 20,000
r = 8% = 8/100 = 0.08
F = double of initial amount = 2 * 20,000 = 40,000
We need to find t:
To solve exponentials, we can take Natural Log (Ln) of both sides:
Using the rule shown below we can simplify and solve:
We can write:
To the nearest year, that would be about 9 years
Since you subtract 6 and you have to find the sixth term, you can do:
-6×5=-30 ( negative shows you're subtracting and since 75 is the first term, then you have to find the difference of the input/term 6-1, the sixth term minus the first)
75-30=45
You can check by actually continuing the pattern.
75,69,63,57,51,45,39......
Answer:
17.38*10^8
Step-by-step explanation:
Step one:
given data
The dividend is 2.26*10^8 (i rewrote the given data, i hope it was mearnt to be so)
divisor is 0.013.
Step two:
Hence the quotient is the whole number gotten when the dividend is divided by the divisor
quotient= 2.26*10^8/0.013.
quotient= 17.38*10^8
Answer:
Step-by-step explanation:
![6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)](https://tex.z-dn.net/?f=6k%5E3%2B10k%5E2-56k%5C%5C2k%283k%5E2%2B5k-28%29%5C%5C%3D2k%5B3k%5E2%2B12k-7k-28%5D%5C%5C%3D2k%5B3k%28k%2B4%29-7%28k%2B4%29%5D%5C%5C%3D2k%28k%2B4%29%283k-7%29)
common factor is 3k-7
