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2 years ago

Answer pls in standard form too

Mathematics

1 answer:

romanna [79]2 years ago

7 0

Answer:

Slope form y=2x+3

Standard form 2x-y=-3

Slope y=3/5x-6

Standard 3x-5y=30

slope y=-3/2x+9

standard 3x+2y=18

slope y=-3x+0

standard = 3x+y=0

Step-by-step explanation:

Slope form y=2x+3

Standard form 2x-y=-3

Slope y=3/5x-6

Standard 3x-5y=30

slope y=-3/2x+9

standard 3x+2y=18

slope y=-3x+0

standard = 3x+y=0

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$\large \mathfrak{Solution : }$

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2 years ago

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3 years ago

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I am Lyosha [343]

Answer:

h=6

Step-by-step explanation:

since $y =hx -2$ is an equation for a line which intersects with the curve $3y^2 = 9x^2 - 6x +1$ . The point of intersection, let's say $(x_1,y_1)$ , should satisfy the two equations. As a result, the value of y in the second equation can be replaced with the value of y in the first equation as the following,

$3y^2 = 3(hx-2)^2 = 9x^2 - 6x +1\\3(h^2x^2 -4hx + 4) = 9x^2 - 6x + 1\\3h^2 x^2 -12hx +12 = 9x^2 - 6x +1$

therefore, the latter equation can be rewritten in a quadratic equation form as the following,

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if the line is tangent to the curve, it means that the line touches the curve at one point, therefore the discernment of the second order equation will be equal to zero for the famous quadratic equation solution.

$b^2 -4ac =0$