Dur rn help pls ))))))))))

Find the common ratio for the following geometric sequence . 3,9,81,...

pshichka [43]

Answer:

3

Step-by-step explanation:

To find the common ratio, take the second term and divide by the first term

9/3 = 3

The common ratio is 3

3 0

4 years ago

20 points.Cynthia has a bag of jellybeans. There are two red jellybeans, one yellow jellybean, and two black jellybeans in her b

solmaris [256]

Answer:

2/5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Identify the values a, b, and c is the first step in using the quadratic formula to find the solution(s) to a quadratic equation

zlopas [31]

The values are a = 7, b = -9, c = -18.

<u>Step-by-step explanation:</u>

The given quadratic equation is $7x^{2} - 9x = 18$

The general form of the quadratic equation is $ax^{2} + bx + c = 0$

where,

a is the coefficient of x².
b is the coefficient of x.
c is the constant term.

Now, you have to modify the given quadratic equation similar to the general form of quadratic equation.

So, bring the constant term 18 to the left side of the equation for equating it to zero.

⇒ $7x^{2} - 9x - 18 = 0$

Compare the above equation with general form $ax^{2} + bx + c = 0$

⇒ a = 7

⇒ b = -9

⇒ c = -18

Therefore, the values of a, b, and c are 7, -9 and -18.

7 0

4 years ago

Read 2 more answers

Use the unit circle to evaluate these expressions:

sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c) For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c. tan(450pi)

For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

4 0

3 years ago

Can someone help?Im confused on what to do on it

spayn [35]

The height is 5 m. The area of a trapezoid is (b1+b2/2)h

8 0

4 years ago