This is how to solve the problem: "What is the transformations of f(x)=(x-2)^2-4"
Looking at the quadratic equation given,
f(x) = (x-2)^2 - 4
It's like seeing product of sum and difference of two squares.
(x-2)^2 - 4
[ (x-2) - 2 ] [ (x-2) + 2 ]
[ x - 2 - 2 ] [ x - 2 + 2 ]
[ x - 4 ] [ x ]
[ x^2 - 4x ]
So the final transformation of f(x) = (x-2)^2 -4 is f(x) = (x^2 - 4x).
In this way, we are able to show how a complicated equation to simple yet equal equation in quadratic form.
Answer:
differ
Step-by-step explanation:
Answer:
y=2/5x+3/5
Step-by-step explanation:
Use the slope formula to get the slope:
m=4/10
m=2/5
The y intercept is 3/5
The equation is y=2/5x+3/5
Answer:
x= square root of 2x-1
Step-by-step explanation:
First you move the 3 to the right side of the equation and since it was multiplied; you have to divide it making it 2x-1.
Then, you have to square it so you can get x by itself and since 2x and -1 do not have a square root you just leave it.
Answer:
No because 16+49 does not equal 121.
Step-by-step explanation:
first make 11 the hypotenuse and 4 and 7 side b and A
Use the pythagorean theorem: A^2+B^2=C^2
4^2+7^2=11^2
16+49=121
