How do I do this man
1 answer:
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Answer:
Option 3: (5, 1)
Step-by-step explanation:
There are several ways of solving for systems of linear equations, either through graphing, substitution, or elimination.
The graphing method is the easiest, as you only need to plot points on the graph using the y-intercepts and the slopes.
I will be demonstrating the <u>graphing method</u>.
Given the systems of linear equations:
Equation 1: y = x - 4
where the <u>slope</u>, <em>m</em> = 1, and <u>y-intercept </u>(0, -4).
Equation2: y = -x + 6
where the <u>slope</u>, <em>m </em>= -1, and <u>y-intercept</u> (0, 6).
The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b).
<h3>Graphing Instructions:</h3>For Equation 1, plot the y-intercept, (0, -4) on the graph. Then use the <u>slope</u>, m = 1 (rise 1 unit, run 1 unit) to plot other points on the graph. Repeat this process until you have enough points to connect a line with.
Repeat these same procedures for graphing Equation 2, start by plotting its y-intercept at (0, 6), and its slope, m = -1 (down 1 unit, run 1 unit).
<h3>Solution: </h3>
The intersection of both lines occurs at point, (5, 1), which is solution to the given systems of linear equations. Therefore, the correct answer is the third option, (5, 1).
Attached is the screenshot of the graphed systems of linear equations, where it shows the point of intersection at (5, 1).
Notice the picture below
the directrix is above the focus point, meaning the parabola is vertical and is opening downwards
now, "p" is the distance from the vertex to the focus point or the directrix, so that means, the vertex is between those two fellows, over the axis of symmetry, x = -2, since "p" is 1 unit, that puts the vertex at -2,5
since the parabola is opening downwards, that means the "p" value is negative, so is -1
the directrix is above the focus point, meaning the parabola is vertical and is opening downwards
now, "p" is the distance from the vertex to the focus point or the directrix, so that means, the vertex is between those two fellows, over the axis of symmetry, x = -2, since "p" is 1 unit, that puts the vertex at -2,5
since the parabola is opening downwards, that means the "p" value is negative, so is -1