Answer:
1) 
2) 49.225
3) 
Step-by-step explanation:
1) To find the expected value of the dice we can use the following equation:
So in our problem the values x will be: 1/1, 1/2, 1/3, 1/4, 1/5 and 1/6 and the probavility for all values is 1/6 so the expected values will be:
2) To find the variance of the expected values we can use the equation:
So for our problem will be:
3) To find the expected value of the dice we can use the following equation:
So in our problem the values x will be: 1, 2, 3, 4, 5 and 6 and the probavility for all values is 1/6 so the expected values will be:
Answer:
The answer is "Choice B, C, and F is correct".
Step-by-step explanation:
The following are choices, which is missing in the question, that can be defined as follows:
A) {x| x ≥ 3} is the domain.
B) The set shall be {y| y ≥ –1}.
C) over the interval (–∞, 3), is the function, that decreases.
D) it's over the duration the function increases its value, that is (–1, ∞).
E) The symmetry axis will be x = – 1.
F) vertex is (3, – 1).
- In choice A, It is incorrect even though f is the domain, which is all true numbers because it has a quadrant function.
- In choice B, it is correct.
- In choice C, It is valid because it was a parable open with vertex so if we exploded view f (3, -1). Because as value opens up, its value with x from-∞ to 3 drops while it goes up from increasing from 3 to ∞.
- In choice D, It is wrong since we have just said f decreases from-∞ to 3. Therefore, f decreases from -1 to 3, too. Therefore, f doesn't grow from -1 to ∞.
- In choice E, It is incorrect because the symmetry axis is x = 3.
- In choice F, it is true.
Hello!!
So what they are giving you is the x,y coordinate of the terminal side of an angle. Meaning 4,10 is the point x=4 and y= 10.
So if we have that, then we can solve for the quadrant that the angle falls in. So for two positive values it tells us it falls in quad 1.
So we have x and y so now use x^2+y^2=h^2 to solve for hypotenuse.
So we get h=sqrt(4^2+10^2)= sqrt(116) or 2*sqrt(29).
Now knowing our trig identities.
Sin= y/h
Cos=x/h
Tan=y/x
Csc=h/y=1/sin
Sec=h/x=1/cos
Cot=x/y=1/tan
So now we have
X=4 Y=10 H=2*sqrt(29)
Now we just use the above identities and plug and chug for your answers. Doing the same one point(4,10)
Sin=10/2*sqrt(29)= (5*sqrt(29))/29
Cos=4/2*sqrt(29)= (2*sqrt(29))/29
Tan=10/4=5/2
Sec=2*sqrt(29)/10= sqrt(29)/5
Csc=2*sqrt(29)/4= 2*sqrt(29)/2
Cot=4/10= 2/5
Now do the same thing as above for all sets of your questions.
Hope this helps!! Any questions please just ask! Thank you so much!
Step-by-step explanation:
it seems we are dealing with subtraction, as the differences between the 1st and second, and between the 2nd and 3rd numbers are equal : -7
so, we can assume that the sequence is created by always subtracting 7.
a1 = 352
a2 = a1 - 7 = 352 - 7 = 345
a3 = a2 - 7 = a1 - 7 - 7 = 352 - 7 - 7 = 338
an = an-1 - 7 = a1 - 7(n-1) = 352 - 7(n-1)
a43 = 352 - 7(43-1) = 352 - 7×42 = 352 - 294 = 58
