Answer:
Step-by-step explanation:
x = 1
(x^2-4x+3=0 or sin(x)=1)
x = 1
( x^2-4x+3=0 or sin(x)=1)
Answer:
0.007
Step-by-step explanation:
0's before other numbers are non-significant. Then you just round your number.
Hope that helps
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer:
C
Step-by-step explanation:
3y - 5x = 15 ... A
y = 5/3 * X +15 .... slope 3/5 , y intercept 15
6y - 10x =30
(6y - 10x) /2 = 30 / 2
3y - 5x = 15 ... B
y = 5/3 * x + 15 ..... slope 3/5 , y intercept 15
∴ Answer is C
Answer:
I think its A.
Step-by-step explanation:
