You know the triangle has a base of 6 meters, and that the formula to find the area of a triangle is 1/2bh or one-half of the base times the height. So, you would plug in 9 meters squared=one half of six times h, or 9m^2=1/2(6)*(h). In simplifying this, you would get 3h=9m^2. Divide both sides by three and get h=3. Hope this helps, and if you need any further explanations, please let me know!

8 0

4 years ago

Given T(-2,4,7) and M(-3,5,2) find the ordered triple that represents TM Then find the magnitude of TM-

Soloha48 [4]

Answer:

(D)

$\overrightarrow{TM} = < 1, -1, 5 >\\|TM|= 3\sqrt{3}$

Step-by-step explanation:

Given T(-2,4,7) and M(-3,5,2)

$\overrightarrow{TM} = \underline{m} - \underline{t}$ where m and t are position vectors. $= - < -3, 5, 2> $ (Subtract corresponding components )$\\= < -2+3, 4- 5, 7-2 >\\= < 1, -1, 5 >$

Given v=<x,y,z>, then the magnitude of v is:

$|v| = \sqrt{x^2+y^2+z^2}, $thus$\\|TM| = \sqrt{(1)^2+(-1)^2+(5)^2}\\= \sqrt{1+1+25}\\ = \sqrt{27} \\= \sqrt{9*3} \\|TM|= 3\sqrt{3}$

7 0

3 years ago