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2 years ago

A-B equals, if A =5x^2-4x-11 and B=-x^2+3x-5

Mathematics

1 answer:

Serga [27]2 years ago

8 0

Answer:

A-B = 6x^2-7x-6

Step-by-step explanation:

A = 5x^2-4x-11

B = x^2+3x-5

A-B = (5x^2-4x-11) - (-x^2+3x-5) = 5x^2-4x-11+x^2-3x+5 = 6x^2-7x-6

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(ASAP NEED TO SUBMIT NOW!!!) What is the Unit Rate for each cyclist?

sveta [45]

Answer:

Unit rates for cyclist A , B, C , D are 12 mile/ hour , 5 mile/hour, 9 mile/hour and 10 mile/hour respectively. Cyclist A is the fastest among the four.

Step-by-step explanation:

Cyclist A can ride 24 miles in 2 hours

so, cyclist A's unit rate is, $\frac {24}{2}$

= 12 mile/hour

Cyclist B's unit rate is, $\frac {5}{1}$

= $\frac {10}{2}$

= $\frac {15}{3}$

= 5 mile/hour

Equation for cyclist C is, y = 9x ,

so, cyclist C's unit rate is , 9 mile/hour

Slope of the graph for cyclist D,

= $\frac {10 -0}{1 - 0}$

= 10

So cyclist D's unit rate is, 10 mile/hour

So, cyclist A is the fastest.

8 0

3 years ago

Let f (x) = 10 x^10 – 5x^8 +2x^6

swat32

This question is way to hard

8 0

3 years ago

The area of a rectangular carpet is 252 square feet. The length is nine feet more than the width. Find the length and the width

Whitepunk [10]

Answer:

<h3>Length = 30 feet </h3><h3>Width = 21 feet </h3>

Given - Length is nine feet more

Area is 252

To find -  Value of length and width

Solution- 

let the width of the carpet be X

therefore length = 9 + X

Area of carpet = Length * width

252 = (9+x) * X

252 = 9x + x²

Solving the equation by splitting middle term

x² + 9x - 252 = 0

x²- 21x + 12x - 252= 0

x ( x - 21) + 12( x - 21) = 0

(x -21)( x + 12) = 0

X = 21 or X = (-12)

Length = 9 + X

= 30 or (-3)

negative is not possible so

length = 30

width = 21

3 0

2 years ago

Can anyone help???????????

Vedmedyk [2.9K]

Given:

The distance between the two buildings on a map = 14 cm

The scale is 1:35000.

To find:

The actual distance in km.

Solution:

The scale is 1:35000.

It means 1 cm on map = 35000 cm in actual.

Using this conversion, we get

14 cm on map = $14\times 35000$ cm in actual.

= $490000$ cm in actual.

= $4.9\times 1000o0$ cm in actual.

= $4.9$ km in actual. $[1\text{ km}=100000\text{ cm}]$

Therefore, the actual distance between two buildings is 4.9 km.

5 0

3 years ago

Out of all the trains currently at Middlebury Station, 5 are

sdas [7]

<h3>Answer: 1/2</h3>

Work Shown:

9 trains headed north

5+4+9 = 18 trains total

P(north) = (# of north)/(# total) = 9/18 = 1/2

8 0

3 years ago