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shutvik [7]
2 years ago
10

Solve for x: 16=2(2x+4)​

Mathematics
2 answers:
frozen [14]2 years ago
8 0

Solution in attachment!

vivado [14]2 years ago
6 0

Answer:

16 = 2(2x + 4) \\ 16 = 4x + 8 \\ 4x = 16 - 8 \\ 4x = 8 \\ x =  \frac{8}{4}  \\ x = 2

hope helpful <3

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100 points / please help! i have no idea what im doing...
Charra [1.4K]

Answer:

b) 5:11

Step-by-step explanation:

count the orange squares and the white squares

7 0
2 years ago
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A bottle holds z ounces of water. A second bottle holds 16 ounces, which is 8/5
Katen [24]

Answer:

The first bottle holds 25 3/5 ounces of water.

Step-by-step explanation:

16 x 8/5

= 16/1 x 8/5

= 128/5

= 25 3/5

5 0
2 years ago
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Max has sticks of lengths 6,7,8 and 10 inches. He wants to make a right triangle for an art project. Which 3 sticks should he us
MrMuchimi
C since that's the only triangle where A^2+B^2=C^2 (36+64=100).
4 0
3 years ago
What is the answer to this question?
WARRIOR [948]

Answer: Lower right corner

============================================

Explanation:

The information that the temperature rises 3 degrees per hour will tell us the slope here. The slope is rise/run = 3/1 = 3. Each time we move up 3 on the y axis, we move 1 spot to the right.

As you can see in the bottom right hand corner graph, we start off at a temperature of 20 degrees. This is the point (x,y) = (0,20)

Then one hour later (x = 1), the temperature y bumps up to y = 23. Another hour passes by (x = 2) and y becomes y = 26. And so on.

3 0
3 years ago
Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3
solmaris [256]

Given:

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

Now,

\cos (u)=-\sqrt{1-\sin^2 (u)}

\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}

\cos (u)=-\sqrt{1-\dfrac{49}{625}}

\cos (u)=-\sqrt{\dfrac{625-49}{625}}

On further simplification, we get

\cos (u)=-\sqrt{\dfrac{576}{625}}

\cos (u)=-\dfrac{24}{25}

Similarly,

\sin (v)=-\sqrt{1-\cos^2 (v)}

\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}

\sin (v)=-\sqrt{1-\dfrac{16}{25}}

\sin (v)=-\sqrt{\dfrac{25-16}{25}}

\sin (v)=-\sqrt{\dfrac{9}{25}}

\sin (v)=-\dfrac{3}{5}

Now,

\cos (u-v)=\cos u\cos v+\sin u\sin v

\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)

\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}

\cos (u-v)=\dfrac{1 17}{625}

Therefore, the value of cos (u-v) is 0.1872.

6 0
2 years ago
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