Please help! Need answered! Please and thank you.

Mathematics

1 answer:

salantis [7]3 years ago

4 0

Answer:

1. lim x→0 7e^x =7

2. lim f(x) does not exist

f(3) = 5

3. 1/12

Step-by-step explanation:

f(x) = 7e^x

lim x→0 7e^x =7

AS we can see from the graph it is around 7

We know that e^0 =1 so 7*1 =7

2. The limit does not exists, because approaching the limit from the left f(3-) is 3. Approaching the limit from the right f(3+) is 5. f(3) = 5 since there is a closed circle at 3 with a value of 5.

3. f(x) = x^ 1/2

We take the derivative

f'(x) = 1/2 x^ (-1/2)

= 1/2 1/( x^.5)

To find it at x=36

= 1/2 * 1/( 36^.5)

= 1/2 * 1/6

= 1/12

Since they are not equal, the limit does not exist.

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

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