Please help! Need answered! Please and thank you.
1 answer:
Answer:
1. lim x→0 7e^x =7
2. lim f(x) does not exist
f(3) = 5
3. 1/12
Step-by-step explanation:
f(x) = 7e^x
lim x→0 7e^x =7
AS we can see from the graph it is around 7
We know that e^0 =1 so 7*1 =7
2. The limit does not exists, because approaching the limit from the left f(3-) is 3. Approaching the limit from the right f(3+) is 5. f(3) = 5 since there is a closed circle at 3 with a value of 5.
3. f(x) = x^ 1/2
We take the derivative
f'(x) = 1/2 x^ (-1/2)
= 1/2 1/( x^.5)
To find it at x=36
= 1/2 * 1/( 36^.5)
= 1/2 * 1/6
= 1/12
Since they are not equal, the limit does not exist.
You might be interested in
There are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.
<h3>What is an exponential function?</h3>It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent y = a^x
where a is a constant and a>1
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have two equations:
y = –2x – 1 and
From the graph, we can see:
There are two intersection points:
(-1, 1) and (-2, 3)
The x coordinates are -1 and -2
x = -1, y = 1
x = -2, y = 3
Thus, there are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.
Learn more about the exponential function here:
#SPJ1
