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MrMuchimi
3 years ago
7

Please help! Need answered! Please and thank you.

Mathematics
1 answer:
salantis [7]3 years ago
4 0

Answer:

1.  lim x→0  7e^x  =7

2.  lim f(x) does not exist

f(3) = 5

3.  1/12

Step-by-step explanation:

f(x) = 7e^x

lim x→0  7e^x  =7

AS we can see from the graph  it is around 7

We know that e^0 =1  so 7*1 =7


2.  The limit does not exists, because approaching the limit from the left f(3-) is 3.  Approaching the limit from the right f(3+) is 5.  f(3) = 5  since there is a closed circle at 3 with a value of 5.


3.  f(x) = x^ 1/2

We take the derivative

f'(x) = 1/2 x^ (-1/2)

    = 1/2 1/( x^.5)

To find it at x=36

     =  1/2 * 1/( 36^.5)

    = 1/2 * 1/6

   = 1/12

Since they are not equal, the limit does not exist.

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