Question

Please help! Need answered! Please and thank you.

Answer 1

Answer:

1.  lim x→0  7e^x  =7

2.  lim f(x) does not exist

f(3) = 5

3.  1/12

Step-by-step explanation:

f(x) = 7e^x

lim x→0  7e^x  =7

AS we can see from the graph  it is around 7

We know that e^0 =1  so 7*1 =7

2.  The limit does not exists, because approaching the limit from the left f(3-) is 3.  Approaching the limit from the right f(3+) is 5.  f(3) = 5  since there is a closed circle at 3 with a value of 5.

3.  f(x) = x^ 1/2

We take the derivative

f'(x) = 1/2 x^ (-1/2)

    = 1/2 1/( x^.5)

To find it at x=36

     =  1/2 * 1/( 36^.5)

    = 1/2 * 1/6

   = 1/12

Since they are not equal, the limit does not exist.