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Temka [501]
3 years ago
7

-4+9 7+(-8) -2+1 6+(-9) 5+(-7) 9+(-5)

Mathematics
1 answer:
krek1111 [17]3 years ago
7 0

Answer:

-14

Step-by-step explanation:

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It would take him 110 minutes to run 10 miles:)
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3 years ago
The equation of a circle is x squared + (y-10) squared = 16.
BaLLatris [955]
The radius of the circle is \sqrt{16}, which is 4
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3 0
4 years ago
A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
PLEASE help test due tonight !!!Use the two-way frequency table to answer questions #14-19
galina1969 [7]

Answer:

14. 1/13

15. 14/15

16. 1/13

17. 15/30=1/2

18. 12/13

19. 12/15

If you are happy with my answers, please give brainliest <3

3 0
3 years ago
What is the answer to 4+(-3)*2
Tamiku [17]
=-2 here you go hope it helps
6 0
4 years ago
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