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Ket [755]
3 years ago
5

Which permission option lets a user view files but not change them?.

Computers and Technology
1 answer:
BARSIC [14]3 years ago
5 0

The read permission allows the user view files but not change them.

<h3>File permission</h3>

Assigning the correct permissions to the files and directories helps prevent data theft because it specify who and what can<em> read, write, modify, and access content</em>. Each file and directory will have three permission categories, these are:

  • Read, write and execute.

The read permission allows the user view files but not change them.

Find out more on file permission at: brainly.com/question/6990309

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Which of the following will most likely result in a decrease in population?
balu736 [363]
The correct answer is B
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3 years ago
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Coupon collector is a classic statistic problem with many practical applications. The problem is to pick objects from a set of o
ahrayia [7]

Answer:

Here is the JAVA program:

public class Main {  //class name

public static void main(String[] args) {   //start of main method

//sets all boolean type variables spades, hearts diamonds and clubs to false initially

   boolean spades = false;  

   boolean hearts = false;

   boolean diamonds = false;

   boolean clubs = false;  

   String[] deck = new String[4];  //to store card sequence

   int index = 0;  //to store index position

   int NoOfPicks = 0;  //to store number of picks (picks count)

   while (!spades || !hearts || !diamonds || !clubs) {   //loop starts

       String card = printCard(getRandomCard());  //calls printCard method by passing getRandomCard method as argument to it to get the card

       NoOfPicks++;   //adds 1 to pick count

       if (card.contains("Spades") && !spades) {  //if that random card is a card of Spades and spades is not false

           deck[index++] = card;  //add that card to the index position of deck

           spades = true;  //sets spades to true

       } else if (card.contains("Hearts") && !hearts) {  //if that random card is a card of Hearts and hearts is not false

           deck[index++] = card;  

           hearts = true;   //sets hearts to true

       } else if (card.contains("Diamond") && !diamonds) {  //if that random card is a card of Diamond and diamonds is not false

           deck[index++] = card;

           diamonds = true;  //sets diamonds to true

       } else if (card.contains("Clubs") && !clubs) {  if that random card is a card of Clubs and clubs is not false

           deck[index++] = card;

           clubs = true;         }     }   //sets clubs to true

   for (int i = 0; i < deck.length; i++) {  //iterates through the deck i.e. card sequence array

       System.out.println(deck[i]);     }  //prints the card number in deck

   System.out.println("Number of picks: " + NoOfPicks);  }   //prints number of picks

public static int getRandomCard() {  //gets random card

   return (int) (Math.random() * 52); }   //generates random numbers of 52 range

public static String printCard(int cardNo) {   //displays rank number and suit

   String[] suits = { "Spades", "Hearts", "Diamonds", "Clubs", };  //array of suits

   String[] rankCards = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10",

           "Jack", "Queen", "King" };   //array of rank

  int suitNo = cardNo / 13;  //divides card number by 13 and stores to suitNo

 int rankNo = cardNo % 13;   //takes modulo of card number and 13 and store it to rankNo

   return rankCards[rankNo] + " of " + suits[suitNo];  }}  //returns rankCard at rankNo index and suits at suitNo index

Explanation:

The program is explained in the comments attached with each line of code. The screenshot of the program along with its output is attached.

8 0
3 years ago
Write a date transformer program using an if/elif/else statement to transform a numeric date in month/day format to an expanded
boyakko [2]

I wrote it in Python because it was quick so i hope this is helpful

Answer:

date = input('Enter Date: ')

split_date = date.split('/')

month = split_date[0]

day = split_date[1]

if month == '1':

   english_month = 'January'

   spanish_month = 'Enero'

elif month == '2':

   english_month = 'February'

   spanish_month = 'Febrero'

elif month == '3':

   english_month = 'March'

   spanish_month = 'Marzo'

elif month == '4':

   english_month = 'April'

   spanish_month = 'Abril'

elif month == '5':

   english_month = 'May'

   spanish_month = 'Mayo'

elif month == '6':

   english_month = 'June'

   spanish_month = 'Junio'

elif month == '7':

   english_month = 'July'

   spanish_month = 'Julio'

elif month == '8':

   english_month = 'August'

   spanish_month = 'Agosto'

elif month == '9':

   english_month = 'September'

   spanish_month = 'Septiembre'

elif month == '10':

   english_month = 'October'

   spanish_month = 'Octubre'

elif month == '11':

   english_month = 'November'

   spanish_month = 'Noviembre'

elif month == '12':

   english_month = 'December'

   spanish_month = 'Diciembre'

US_English = f'{english_month} {day}'

International_Spanish = f'{day} {spanish_month}'

print(f'US English Form: {US_English}')

print(f'International Spanish Form: {International_Spanish}')

Input:

3/5

Output:

US English Form: March 5

International Spanish Form: 5 Marzo

Explanation:

You start by taking input from the user then splitting that at the '/' so that we have the date and the month in separate variables. Then we have an if statement checking to see what month is given and when the month is detected it sets a Spanish variable and an English variable then prints it to the screen.

Hope this helps.

7 0
3 years ago
Which technique/concept can be use toimplement multiple inheritances<br> in java?
LiRa [457]

Answer:

Interface

Explanation:

Java does not supports multiple inheritance by class, but we can implement multiple inharitacnce in  java using interface, with interface we uses implements keyword.

Example-

Declare interface like below code -

interface parent{

}

and use in child class like below code -

class Child1 implements interface{

}

class Child2 implements interface{

}

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What was the #1 song in 1987 and who was the artist
Veronika [31]
Billboard magazine said it was "Walk Like an Egyptian" by The Bangles.
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