B) For Military Purposes but around the 1970s they became widely available to consumers.
A casual game is a video game targeted at or used by casual gamers. Casual games may exhibit any type of gameplay or genre. They are typically distinguished by simple rules and by reduced demands on time and learned skill, in contrast to more complex hardcore games. They typically impose low production and distribution costs on the producer. Casual games are often played on a personal computer online in web browsers, but are also popular on game consoles and mobile phones.
Hope this helped. Have a great day! :D
Answer:
see explaination
Explanation:
I made use of python program to solve this.
text file name with fun.txt.
6 fun. 3 hello 10 <> 2 25 4 wow!
Program code:
import re
file = open('fun.txt','r') #for reading file
strings="" #declaring empty string
for k in file:
strings=strings+k #all character in file is storing in strings variable for do operations
pattern = '\s' #for pattern \s is for space
result = re.split(pattern, strings) #split the string with space
for k in range(len(result)): #loop through the list of string
if(k%2) == 0: #checking for integer to time of string
p=int(result[k])
print(result[k+1] *p) #print times of the string(k+1)
Check attachment for output
Cleaning up a system helps clear up the space on the drives. It may also clear up processor usage, ram usage if you uninstall programs that automatically started when the system booted. You may also delete some unwanted programs in the process.
Answer:
Explanation:
The following code is written in Java and is a function/method that takes in an int array as a parameter. The type of array can be changed. The function then creates a counter and loops through each element in the array comparing each one, whenever one element is found to be a duplicate it increases the counter by 1 and moves on to the next element in the array. Finally, it prints out the number of duplicates.
public static int countDuplicate (int[] arr) {
int count = 0;
for(int i = 0; i < arr.length; i++) {
for(int j = i + 1; j < arr.length; j++) {
if(arr[i] == arr[j])
count++;
}
}
return count;
}
