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3 years ago

What is the markup percent on a diamond for which the markup is $870 and the selling price is $2870?

Mathematics

1 answer:

ryzh [129]3 years ago

3 0

Answer:

30.31%

Step-by-step explanation:

Mark up on selling price is given by markup*100%/selling price

In this case, markup is given as $870 while the selling price is $2870 hence the percentage of narkup to selling price will be given by $\frac {870\times 100}{2870}=30.313588850174\approx 30.31$

Therefore, the percentage of markup to selling price is approximately 30.31%

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3 years ago

A firm has the marginal-demand function where D(x)=-1400x÷√25-x² is the number of units sold at x dollars per unit. Find the dem

borishaifa [10]

The equation of the demand function is D(x) = 1400√(25-x²) + 11400

<h3>How to determine the demand function?</h3>

From the question, we have the following parameters that can be used in our computation:

Marginal demand function, D'(x) = -1400x÷√25-x²

Also, we have

D = 17000, when the value of x = 3

To start with, we need to integrate the marginal demand function, D'(x)

So, we have the following representation

D(x) = 1400√(25-x²) + C

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17000 = 1400√(25-3²) + C

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So, we have

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Substitute C = 11400 in D(x) = 1400√(25-x²) + C

D(x) = 1400√(25-x²) + 11400

Hence, the function is D(x) = 1400√(25-x²) + 11400

Read more about demand function at

brainly.com/question/24384825

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dezoksy [38]

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