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Viefleur [7K]
3 years ago
7

Misha surveyed students in her school about what writing tool they use. She found that 75 use pens; 30 of the pen users are boys

. She also found that 28 boys and 32 girls use pencils.
Mathematics
2 answers:
Nina [5.8K]3 years ago
6 0

a =  ✔ 45

b =  ✔ 60

c =  ✔ 58

d =  ✔ 77

e =  ✔ 135

crimeas [40]3 years ago
5 0

Answer:

a.) 45

b.) 60

c.) 58

d. )77

e.) 135

Step-by-step explanation:

i took the test

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mote1985 [20]

Answer:  y= -5x - 1

y = -5.2 + 7

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4 0
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Can someone help me out my grads are bad
Pani-rosa [81]

Answer:

162

Step-by-step explanation:

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I need to know what the volume of the cone in cubic inches please
ivolga24 [154]

Answer:

V = 118 in³

Step-by-step explanation:

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3 years ago
Given that tangent theta = negative 1, what is the value of secant theta, for StartFraction 3 pi Over 2 EndFraction less-than th
vivado [14]

The value of tangent theta is equal to the negative 1.  At this value the value of secant theta is \sqrt{2}.

<h3>What is tangent theta?</h3>

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

\rm tan\theta=\dfrac{sin \theta}{cos \theta}

Given information-

The value of tangent theta is equal to the negative 1.

\tan \theta=-1

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

\rm tan\theta=\dfrac{sin \theta}{cos \theta}

The value of tangent theta is equal to the negative 1. Thus put the value in above expression as,

\rm -1=\dfrac{sin \theta}{cos \theta}\\

Simplify it further as,

\rm -cos \theta=sin \theta

When the value of cosine and sine theta is equal, then the angle exist in 4th quadrant with the value of \dfrac{7\pi}{4}. Which extent to the \sqrt{2}/2 for the cosine function.

In the trigonometry cosine theta is the reciprocal of the secant theta. Thus,

\rm \dfrac{1}{sec\theta}=\dfrac{\sqrt{2}}{2}\\sec\theta=\sqrt{2}

Thus the value of secant theta is \sqrt{2}

Learn more about the tangent theta here;

brainly.com/question/29190

4 0
3 years ago
Read 2 more answers
Can I please get some help on this...I have tried to many times...
Bezzdna [24]

Answer: A

Step-by-step explanation:

First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.

\sqrt{x-2} =0

When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.

5 0
3 years ago
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