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nataly862011 [7]
3 years ago
8

Adam needs to drive a distance of 372 miles to attend a seminar in New

Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0

Based on the total distance to the seminar and the proportion driven , the number of miles driven is<u> 124 miles. </u>

The driver has to drive 372 miles to get to the seminar and has driven 1 / 3 of this distance.

<h3>Number of miles driven </h3>

The number of miles Adam has driven is:

<em>= Fraction of distance driven x Total distance</em>

= 1 / 3 x 372

= 124 miles

In conclusion, Adam has driven 124 miles.

Find out more about proportions at brainly.com/question/261234.

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Which ordered pairs make both inequalities true? Check all that apply.
Margaret [11]
When an <span>inequality is true it is in the region that both are shaded, so the answer would be 1,1 and 2,2</span>
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3 years ago
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4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
Consider the tables that represent ordered pairs corresponding to a function and its inverse. When comparing the functions using
lara31 [8.8K]

Answer:

D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

Step-by-step explanation:

The missing tables are:

First table  

x:    0  1    2

f(x): 1   10  100

Second table

x:         1000   100   10

f^-1(x):  3          2       1  

Option A is not correct because f(x) has a y-intercept at (0, 1)

If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct

Option C is not correct because the domain of f^-1(x) is associated with x values.

Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa

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4 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
20 POINTS <br> Can someone please explain what I did wrong?
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Your diagram is correct.

I would have however written the Given as stated

Given :

XB≅XA≅AY≅YB ( If they are equidistant then they are all the same distance, thus the values will all be equal)

Prove:

<x≅<b≅<y≅<a (this is because a square is formed) < is angle

XM≅YM≅AM≅MB (The fact that the previous statements are true means that this is a square, if M is the midpoint than all these segments are equal)

MX≅MY

Im not sure what you did wrong besides maybe you didn't prove it well enough, everything is correct that you have written. I cant read the pen but it looks like you were missing a step.


3 0
3 years ago
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