x = perimeter
x<156
length = 66
so, in order to calculate perimeter you need to add two lengths and two widths
so
156 (perimeter) - 2 (66) = two widths
156 - 132 = 24 (remember this number is two widths added together)
so 24 twice the width SO 12 would be the number that the width can't be larger than
the width has to be less than 12
w < 12
Subtract x2 from x1 to get -7. After that subtract y2 from y1 to receive 3. That leaves you with -7/3 which simplified is -2.1333*
I need help to solve this problems can somebody help me
The rest of the question is the attached figure
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solution:
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As show in the attached figure
∠M = ∠R = 54.4°
∠N = ∠T = 71.2°
∠O = 180° - (∠M + ∠N) = 180° - (54.4°+71.2°) = 54.4°
∠S = 180° - (∠R + ∠T) = 180° - (54.4°+71.2°) = 54.4°
∠O = ∠S = 36°
∴ Δ MNO is similar to Δ RTS
So, the correct statement:
The triangles each have two given angle measures and one unknown angle measure.
Answer: The answer should be 0.125
Step-by-step explanation: