For example, 5 can be written as 5/1. The natural numbers, whole numbers, and integers are all subsets of rational numbers. In other words, an irrational number is a number that can not be written as one integer over another. It is a non-repeating, non-terminating decimal.
It’s 4 because y is a variable plus any number in front of a variable makes it a coefficient
<span>Let us start with the percentage of premium paid by Javier. Since the employer pays 43%, the remaining 57% (100-43) is paid by Javier. Now let us find out how much is deducted from his paychecks during the year. In one month, $157.38 x 2 = $314 .76 is deducted by the employer. So in 12 months, the amount equal to 57% of the health premium will be $314.76 x 12 = $3777.12.
If $ 3777.12 is 57% of a certain number, to find the number, multiply $3777.12 with the reciprocal of the fraction. (57/100)
So the unknown number = $3777.12 * 100/57 = $6626.53
Javier's total annual health premium, therefore, is $6626.53</span>
Answer:
1) A
2) min; min; max; max
3) y = x² + 5x - 3
Step-by-step explanation:
f(x) = x² + 2(x)(5) + 5² - 5² + 24
f(x) = (x + 5)² - 25 + 24
f(x) = (x + 5)² - 1
In ax² + bx + c,
if a > 0, it's a min
if a < 0, it's a max
y = ax² + bx + c
Using (0,-3)
-3 = a(0)² + b(0) + c
c = -3
y = ax² + bx - 3
Using (1,3)
3 = a + b - 3
a + b = 6
Using (-1,-7)
-7 = a(-1)² + b(-1) - 3
-7 + 3 = a - b
a - b = -4
b = a + 4
a + (a + 4) = 6
2a = 2
a = 1
b = 5
y = x² + 5x - 3
Ok so standard form is a bit tricky, but I’ll help explain
Here’s and example:
If you have 2x+5y=10 here is how you would solve it
First you divide the x value by what the number is equal to (in our example, 10), and then we get 10/2 is 5. So now we know that
x is equal to five
Keep that in mind. Now we just have to do the same thing for the y value. 5/10 is 2, so you know that
y is equal to two
NOW you put those two together, and graph on the intercepts (the positions on the y and x axis where the lines intercept)
You would put a line on the x axis at 5, and on the y axis at 2
If you have any questions, you can ask