The answer is 80! If you ever see any angle like that where it’s just two lines (I don’t know how to explain it/forgot what it’s called) it will be the same as the other angle.
keeping in mind that when the logarithm base is omitted, the base 10 is assumed.
![\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x](https://tex.z-dn.net/?f=%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%3D2%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D2%5Cimplies%2010%5E2%3Dx%5Cimplies%20100%3Dx)
Answer:
If one −5s−7(8s−1): -61s+7
If two −5s−7(8s−1): -112s+14
Step-by-step explanation:
-5s-7(8s-1)
Multiply -7 onto 8s and -1:
-5s-56s+7
add -5s and -56s:
-61s+7
−5s−7(8s−1)−5s−7(8s−1)
Multiply both -7 to 8s and -1
-5s-56s+7-5s-56s+7
add:
-112s+14