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wolverine [178]
3 years ago
15

Which of the following list of values contain rational numbers only ?

Mathematics
1 answer:
AfilCa [17]3 years ago
6 0

9514 1404 393

Answer:

  -√81, (√7)/(√7), 4.16666...

Step-by-step explanation:

The irrational values in the first three choices are ...

  • π
  • √28
  • √50

The values in the last choice, expressed as integers or fractions are ...

  -9, 1, 25/6

The last list is all rational numbers.

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Westkost [7]

all real numbers are greater than or equal to the equation

7 0
3 years ago
Help. I need both. Please
Darya [45]
Anything to the power of 0 is 1

So for the top, 2^0 = 1
For the bottom, 10^0 = 1


It is not 0, because anything that ends with 0/0 is <em>undetermined</em>, and will not result in an answer

hope this helps
6 0
3 years ago
Choices;<br> a) 21.8°<br> b) 35.2°<br> c) 45.1°
kifflom [539]

Answer:

\displaystyle a) \: {x}^{ \circ}  =  21.8 ^{ \circ}

Step-by-step explanation:

we are given opposite and adjacent

we want to figure out x°

remember that,

\displaystyle \: \tan( \theta)  =  \frac{opp}{adj}

where our opp is 5 and adj is 12.5

let \theta be x°

so

\displaystyle \: \tan(  {x}^{ \circ} )  =  \frac{5}{12.5}

\displaystyle \: {x}^{ \circ}  =  \arctan \left( \frac{5}{12.5}  \right)

by using calculator

\displaystyle \: {x}^{ \circ}  =  21.8

hence,

our answer is a

6 0
3 years ago
Find the distance CD rounded to the nearest tenth
motikmotik

Answer:

CD ≈ 15.0

Step-by-step explanation:

calculate CD using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = C (7, - 4) and (x₂, y₂ ) = D (- 8, - 5)

CD = \sqrt{(-8-7)^2+(-5-(-4))^2}

     = \sqrt{-15)^2+(-5+4)^2}

     = \sqrt{225+(-1)^2}

     = \sqrt{225+1}

     = \sqrt{226}

     ≈ 15.0 ( to the nearest tenth )

 

3 0
2 years ago
Can someone help me with this problem
IRISSAK [1]

If your looking for the value of "x" it is 4.

Hope this helped!

7 0
2 years ago
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