All categories

2 years ago

Iiiiiiiiiiiiiiiiiiiii nnnnnnneeeeeeeeeeeeeeeeeeeeed heeeeeeeeelllllllllppp

Mathematics

1 answer:

zaharov [31]2 years ago

5 0

Answer:

$y=\frac{1}{2}x+5$

Step-by-step explanation:

Step 1: identify the slope

$m=\frac{y_{2}-y_1 }{x_2-x_1} \\m=\frac{9-5}{8-0}\\m=\frac{4}{8}\\m=\frac{1}{2}$

Step 2: identify the y-intercept:

$b=5$

Step 3: put everything into an equation:

$y=\frac{1}{2}x+5$

You might be interested in

A truck can at most be filled with 20 ton. If there are currently 14 ton goods there already, write an inequality representing t

Rom4ik [11]

Answer:

$x + 14 \leq 20$ , x = 6 ton

Step-by-step explanation:

The truck can be filled with a total of 20 ton.

There are already 14 ton inside the truck, so if we call x the weight of goods that we can still add into the truck, we know that (x+14) must be equal at most at 20. Therefore, the inequality becomes:

$x+14\leq 20$

Solving it, we find

$x\leq 6$

which means that the most amount of goods that could be added to the truck is 6 tons.

4 0

3 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

4 0

2 years ago

-8(8v + 1) - 2 = -394

Bess [88]

Answer:

v = 6

Step-by-step explanation:

Solve for v:

-8 (8 v + 1) - 2 = -394

-8 (8 v + 1) = -64 v - 8:

-64 v - 8 - 2 = -394

Grouping like terms, -64 v - 8 - 2 = -64 v + (-8 - 2):

-64 v + (-8 - 2) = -394

-8 - 2 = -10:

-10 - 64 v = -394

Add 10 to both sides:

(10 - 10) - 64 v = 10 - 394

10 - 10 = 0:

-64 v = 10 - 394

10 - 394 = -384:

-64 v = -384

Divide both sides of -64 v = -384 by -64:

(-64 v)/(-64) = (-384)/(-64)

(-64)/(-64) = 1:

v = (-384)/(-64)

The gcd of -384 and -64 is -64, so (-384)/(-64) = (-64×6)/(-64×1) = (-64)/(-64)×6 = 6:

Answer: v = 6

3 0

3 years ago

Read 2 more answers

If cos A = k, then the value of the expression (sin A)(cos A)(tan A) is equivalent to:

sukhopar [10]

Answer:

1-k^2

Step-by-step explanation:

tan A= sin A/cos A

(sin A)(cos A)(sin A/cos A)=(sin A)^2

(sin A) ^2 + (cos A) ^2= 1

(sin A) ^2=1-(cos A) ^2

(sin A)^2= 1 - k^2

4 0

2 years ago

Read 2 more answers

Greg is volunteering at a track meet. He is in charge of providing the bottled water. Greg knows these facts:

GuDViN [60]

Answer: There are 819 fewer number of cases of water bottle that all athlete, all coaches and all judges will get.

Step-by-step explanation:

Since we have given that

Number of days the meeting is going on = 3 days

Number of athletes = 117

Number of coaches = 7

Number of judges = 4

Number of bottles given to each athlete each day = 4

Total number of bottles total athlete for 3 days will get is given by

$117\times 4\times 3\\\\=1404$

Number of bottles given to each coach each day = 3

Total number of bottles total coach for 3 days will get is given by

$7\times 3\times 3\\\\=63$

Number of bottles given to each judge each day = 2

Total number of bottles total judge for 3 days will get is given by

$4\times 3\times 2\\\\=24$

Number of cases of water bottle is given to athletes is given by

$\frac{1404}{24}$

Number of cases of water bottle is given to coaches is given by

$\frac{63}{24}$

Number of cases of water bottle is given to judges is given by

$\frac{24}{24}$

We need to find the fewer number of cases that all athlete , all coaches and all judges will get

$\text{L.C.M. of }\frac{1404}{24},\frac{63}{24},\frac{24}{24}\\\\=\frac{L.C.M.\ of\ 1404,63,24}{H.C.F.\ of\ 24,24,24}\\\\=\frac{19656}{24}\\\\=819$

Hence, there are 819 fewer number of cases of water bottle that all athlete, all coaches and all judges will get.

5 0

2 years ago

Read 2 more answers