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A jar holds 3 1/2 cups of water. How much is this in fluid ounces?

denpristay [2]

I believe it is twenty eight as there is eight fluid oz in one cup.

8 0

3 years ago

✓

FrozenT [24]

Answer:

D : || ,|||, |V is the answer

6 0

3 years ago

Clint randomly picks a card from a collection of eight hearts and two spades. Which situation can he represent with this simulat

lions [1.4K]

Clint randomly picks a card from a collection of eight hearts and two spades. Which situation can he represent with this simulation?

I think the correct answer for this question is :
A) randomly picking a napkin from a collection of four white napkins and one blue one

As you can see the probabilities are the same and that's how you figure your answer out.

Hope this helps!

8 0

4 years ago

Read 2 more answers

1. There were 88 birds in the tree and then b of the birds flew away. Write an expression that shows how many birds are in the t

avanturin [10]

Answer:

1. 88 - b

Since there is 88 birds and a few of them flew away. You know b represents the amount of birds present.

2. 73 + d

Since he is earning d (amount of dollars) so what you have to do is add the amount of dollars, d, to the orginial amount, which is 73.

3. 23 x g

Since Kurt has 23 miles. If he drives 23 miles to a gallon and we have g gallons then we would multiply to find how far he can drive.

4 0

3 years ago

A chemical plant has an emergency alarm system. When an emergency situation exists, the alarm sounds with probability 0.95. When

Lapatulllka [165]

Answer:

6.56% probability that a real emergency situation exists.

Step-by-step explanation:

We have these following probabilities:

A 0.4% probability that a real emergency situation exists.

A 99.6% probability that a real emergency situation does not exist.

If an emergency situation exists, a 95% probability that the alarm sounds.

If an emergency situation does not exist, a 2% probability that the alarm sounds.

The problem can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem:

What is the probability of a real emergency situation existing, given that the alarm has sounded.

P(B) is the probability of there being a real emergency situation. So $P(B) = 0.004$ .

P(A/B) is the probability of the alarm sounding when there is a real emergency situation. So P(A/B) = 0.95.

P(A) is the probability of the alarm sounding. This is 95% of 0.4%(real emergency situation) and 2% of 99.6%(no real emergency situation). So

P(A) = 0.95*0.04 + 0.02*0.996 = 0.05792

Given that the alarm has just sounded, what is the probability that a real emergency situation exists?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.004*0.95}{0.05792} = 0.0656$

6.56% probability that a real emergency situation exists.

6 0

3 years ago

Please help me somebody will​

Please help me somebody will