Answer:
Trent has 6 quarters and 5 dimes.
Step-by-step explanation:
Consider the provided information.
Let q = Number of quarters
d = Number of dimes.
Trent has 11 quarters and dimes.
The worth of a quarter is 25 cents.
The worth of a dimes is 10 cents
Substitute the value of q in above equation.
Substitute the value of d in
Hence, Trent has 6 quarters and 5 dimes.
Answer:
The return trip take 5 minutes 27 seconds
Step-by-step explanation:
Let
x -----> the time it take the cheetah travels to go from its resting place to a rock near a river in hours
y ----> the time it take the cheetah the return trip to its resting place in hours
we know that
The distance from its resting place to a rock near a river is the same that the return trip
The average speed multiplied by the time is equal to distance
so
The total time is 15 minutes
Convert to hours
15 min=15/60 hours
x+y=(15/60)
x+y=1/4
4x+4y=1 -----> equation A
40x=70y ----> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point ( 0.1591,0.0909)
see the attached figure
The time it take the cheetah travels to go from its resting place to a rock near a river is 0.1591 hours
The time it take the cheetah the return trip to its resting place is 0.0909 hours
Convert to minutes and seconds
0.0909 hours=0.0909(60)=5.454 minutes
o.454 minutes=0.454(6)=27.24 seconds
therefore
The return trip take 5 minutes 27 seconds
<u><em>To the river</em></u>
The time it take the cheetah travels to go from its resting place to a rock near a river is 0.1591 hours
The rate is 40 mph
To find out the distance multiply the average rate by the time
<em>Find out the distances</em>
The distance from its resting place to a rock near a river is
<u><em>From the river</em></u>
The time it take the cheetah the return trip to its resting place is 0.0909 hours
The rate is 70 mph
To find out the distance multiply the average rate by the time
<em>Find out the distances</em>
The distance of the return trip is
Both distances are the same
