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victus00 [196]
2 years ago
8

Best Buy is having a sale. iPads are marked down 20%. Of the original cost is $399, how much will you pay?

Mathematics
2 answers:
iren [92.7K]2 years ago
5 0
It is


$79.80 I believe
According to me?
iris [78.8K]2 years ago
4 0

Answer:

$319.20

Step-by-step explanation:

Find the amount being reduced: 399*20%=79.8

Subtract the numbers: 399-79.8=319.2

The final answer is $319.20

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Step-by-step explanation:

I'm sorry if this doesn't make sense but I hope it helps

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3 years ago
When rolling two dice, Which probability has the same number of chances as rolling a P(1)?
Harman [31]

Answer:

\frac{1}{6})

Step-by-step explanation:

probability= <u>no of possible outcom</u><u>e</u>

total outcome

therefore p(1)=

\frac{2}{12}

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3 0
3 years ago
Choose the best definition for the following term: exponent. (1 point) Shorthand that tells how many times the base is used as a
babunello [35]
An exponent is the number or value being raised to a power.
8 0
3 years ago
At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4
wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

1.

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}

2.

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\  \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}

3.

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\  \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\  \\ \therefore E_1\equiv E_2=55580ft \end{gathered}

6 0
1 year ago
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