Sorry cant help you, that's a tough nut to crack! good luck though!
Area of a circle for (360degrees) = pi*(r^2)
Area of part of a circle with angle θ=(θ/360)*(pi*)*(r^2)
<span>(θ/360)*pi*(6^2)=12*pi
</span>solving, <span>θ=(12/36)*360
</span><span>θ=120 degress
</span>
The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
To learn more about the factor visit:
brainly.com/question/25829061
65x^2 + 212x - 133
you have to use the quadratic formula
x=( -b +/- √b²-4ac) / 2a
a is 65
b is 212
c is 133
because the first value is squared you will have 2 answers
x= 7/13
x= - 19/5
Answer:
b because it just is
Step-by-step explanation:
