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3 years ago

10

What is ten times as much as 0.09

2 answers:

zzz [600]3 years ago

6 0

10×0.09= 0.9 it moves the decimal to the right right once

Sophie [7]3 years ago

3 0

The answer you are searching for is .9

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Can you help me with this question please!

Crazy boy [7]

Answer:

so the first one i think is 1 and the second one is 4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

I need help with math

Keith_Richards [23]

$\frac{1}{5} + \frac{3}{4} \times \frac{3}{5} = \\$

$\frac{1}{5} + \frac{9}{20} = \\$

$\frac{4}{20} + \frac{9}{20} = \\$

$\frac{13}{20} \\$

4 0

2 years ago

t hits the square dartboard shown below at a random point. Find the probability that the dart lands in the shaded circular regio

masha68 [24]

Given:

Required:

To find the probability that the dart land will be in the shaded region.

Explanation:

Area of the circle is given by the formula:

$A=\pi r^2$

Where r = radius

Thus the area of the circular region

$\begin{gathered} =(3.14)\times(2)^2 \\ =3.14\times4 \\ =12.56\text{ square in.} \end{gathered}$

The area of the square is given by the formula:

$=(side)^2$

Thus the area of the given square

$\begin{gathered} =(6)^2 \\ =36\text{ square in.} \end{gathered}$

The probability of an event is given by the formula:

$P=\frac{number\text{ of possible outcomes}}{Total\text{ number of outcomes}}$

The probability that the dart land will be in the shaded region

$=\frac{Area\text{ of the shaded region}}{Area\text{ of the square}}$

Thus probability

$\begin{gathered} P=\frac{12.56}{36} \\ P=0.3488 \\ P=0.349 \end{gathered}$

Final answer:

Thus the probability that the dart land will be in the shaded region is 0.349.

6 0

1 year ago

An equation of the perpendicular bisector of the line segment with end points (3,0) and (-3,0) is

Norma-Jean [14]

Answer:

$x = 0$

Step-by-step explanation:

Given

$(x_1,y_1) = (3,0)$

$(x_2,y_2) = (-3,0)$

Required

The equation of the perpendicular bisector.

First, calculate the midpoint of the given endpoints

$(x,y) = 0.5(x_1 + x_2, y_1 + y_2)$

$(x,y) = 0.5(3-3, 0+ 0)$

$(x,y) = 0.5(0, 0)$

Open bracket

$(x,y) = (0.5*0, 0.5*0)$

$(x,y) = (0, 0)$

Next, determine the slope of the given endpoints.

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{0 - 0}{-3- 3}$

$m = \frac{0}{-6}$

$m = 0$

Next, calculate the slope of the perpendicular bisector.

When two lines are perpendicular, the relationship between them is:

$m_2 = -\frac{1}{m_1}$

In this case:

$m = m_1 = 0$

So:

$m_2 = -\frac{1}{0}$

$m_2 = unde\ fined$

Since the slope is $unde\ fined$ , the equation is:

$x = a$

Where:

$(x,y) = (a,b)$

Recall that:

$(x,y) = (0, 0)$

So:

$a = 0$

Hence, the equation is:

$x = 0$

5 0

3 years ago

Compute the probability of the event E1 that Bob wins in a duel against Eve alone, assuming he shoots first. (Hint: Let x be the

skad [1K]

Answer: Hello your question is incomplete attached below is the missing

n ( 1 + n )

Step-by-step explanation:

P( Bob hits target ) = 1/3

P( Eve hits target ) = 2/3

P( Carol hits target ) = 1

<u>Compute the P that Bob wins in a duel against Eve alone</u>

P(Bob hits the target in first shot ) = n = 1/3

P(Bob hits the target in second shot ) = n^2 = ( 1/3 * 1/3 ) = 1/9

hence the probability of Bob winning( i.e. P( Bob wins Event E1 ) = n + n^2 = n ( 1 + n )

6 0

3 years ago