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Gnesinka [82]
2 years ago
9

Three consecutive odd integers have a sum of 51. what is the smallest integer

Mathematics
1 answer:
nalin [4]2 years ago
7 0

Answer:

15

Step-by-step explanation:

Let 2n+1 be the first odd integer.

Therefore, the consecutive odd integers will be 2n+3 and 2n+5

If the sum of the consecutive odd integers is 51 then:

⇒ 2n + 1 + 2n + 3 + 2n + 5 = 51

⇒ 6n + 9 = 51

⇒ 6n = 42

⇒ n = 7

To find the values of the integers, substitute the found value of n into the expressions:

  • First integer:       2(7) + 1 = 15
  • Second integer:  2(7) + 3 = 17
  • Third integer:      2(7) + 5 = 19

Therefore, the three consecutive odd integers that sum to 51 are <u>15, 17 and 19</u>.  The smallest of which is 15.

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nevsk [136]

Answer:

Approximately 16% of adult women have feet longer than 27.2 cm.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The feet of the average adult woman are 24.6 cm long

This means that \mu = 24.6

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The proportion is 1 subtracted by the p-value of Z when X = 27.2. So

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Approximately 16% of adult women have feet longer than 27.2 cm.

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Step-by-step explanation:

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