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Gnesinka [82]
2 years ago
9

Three consecutive odd integers have a sum of 51. what is the smallest integer

Mathematics
1 answer:
nalin [4]2 years ago
7 0

Answer:

15

Step-by-step explanation:

Let 2n+1 be the first odd integer.

Therefore, the consecutive odd integers will be 2n+3 and 2n+5

If the sum of the consecutive odd integers is 51 then:

⇒ 2n + 1 + 2n + 3 + 2n + 5 = 51

⇒ 6n + 9 = 51

⇒ 6n = 42

⇒ n = 7

To find the values of the integers, substitute the found value of n into the expressions:

  • First integer:       2(7) + 1 = 15
  • Second integer:  2(7) + 3 = 17
  • Third integer:      2(7) + 5 = 19

Therefore, the three consecutive odd integers that sum to 51 are <u>15, 17 and 19</u>.  The smallest of which is 15.

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