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Gnesinka [82]
2 years ago
9

Three consecutive odd integers have a sum of 51. what is the smallest integer

Mathematics
1 answer:
nalin [4]2 years ago
7 0

Answer:

15

Step-by-step explanation:

Let 2n+1 be the first odd integer.

Therefore, the consecutive odd integers will be 2n+3 and 2n+5

If the sum of the consecutive odd integers is 51 then:

⇒ 2n + 1 + 2n + 3 + 2n + 5 = 51

⇒ 6n + 9 = 51

⇒ 6n = 42

⇒ n = 7

To find the values of the integers, substitute the found value of n into the expressions:

  • First integer:       2(7) + 1 = 15
  • Second integer:  2(7) + 3 = 17
  • Third integer:      2(7) + 5 = 19

Therefore, the three consecutive odd integers that sum to 51 are <u>15, 17 and 19</u>.  The smallest of which is 15.

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(0, -2) (Answer B)

Step-by-step explanation:

Recall that the y-axis represents x = 0.  The blue line crosses (intercepts) the y-axis when x = 0.  The corresponding y-coordinate is -2.  Thus, the y-intercept is (0, -2), or just -2.

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Step-by-step explanation:

For 2 people it uses 1 1/3 cups

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8) What are the measures of angles x, y, and z?
UkoKoshka [18]

Step-by-step explanation:

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2 years ago
Read 2 more answers
Math Help!!! Can someone please solve this?? I will give you Brainliest!
Burka [1]

Triangles PQR and PSR are right triangles, with both QR = SR = 5 (since these are radii of the circle R).

TR is also a radius of the circle, so TR = 5, making PR = 4 + TR = 9.

Because PQR and PSR are right triangles, we can compute the length of the missing side, which will be equal. By the Pythagorean theorem,

PQ^2 + QR^2 = PR^2

PQ^2 + 5^2 = 9^2

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PQ = √56 = 2√14

Then the perimeter of PQRS is

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4 0
3 years ago
Help! Please! Geometry!!
DiKsa [7]

9.

By the Segment Addition Postulate, SAP, we have

XY + YZ = XZ

so

YZ = XZ - XY = 5 cm - 2 cm = 3 cm

10.

M is the midpoint of XZ=5 cm so

XM = 5 cm / 2 =  2.5 cm

11.

XY + YM = XM

YM = XM - XY = 2.5 cm - 2 cm = 0.5 cm

12.

The midpoint is just the average of the coordinate A(-3,2), B(5,-4)

M = (A+B)/2 = \left( \dfrac{-3 + 5}{2}, \dfrac{2 + -4}{2} \right)

Answer: M is (1,-1)

You'll have to plot it yourself.

13.

For distances we calculate hypotenuses of a right triangle using the distnace formula or the Pythagorean Theorem.

AB^2 =(5 - -3)^2 + (-4 - 2)^2 = 8^2 + 6^2 = 100

Answer: AB=10

M is the midpoint of AB so

Answer: AM=MB=5

14.

B is the midpoint of AC.   We have A(-3,2), B(5,-4)

B = (A+C)/2

2B = A + C

C = 2B - A

C = ( 2(5) - -3, 2(-4) - 2 ) = (13, -10)

Check the midpoint of AC:

(A+C)/2 = ( (-3 + 13)/2, (2 + -10)/2 ) = (5, -4) = B, good

Answer: C is (13, -10)

Again I'll leave the plotting to you.

5 0
3 years ago
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