Diagonal = √2 * side = 3√2 *√2 = 3*2 = 6
If period of

is one-half the period of

and
<span>

has a period of 2π, then

and

.
</span>
To find the period of sine function

we use the rule

.
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f is sine function where f (0)=0, then c=0; with period

, then

, because

.
To find a we consider the condition

, from where

.
If the amplitude of

is twice the amplitude of

, then

has a product factor twice smaller than

and while period of

<span> </span> is 2π and g(0)=0, we can write

.
Answer:
0 real # solution
Step-by-step explanation:
b^2-4ac<1 is equal to 0 real number solution and
-5(2+1)=-22+10
-5(2+1)=-12
which is less than 1
Answer:
I found the x values. Figure out the lengths by substituting the x-values!
Step-by-step explanation:
Feel free to ask if you don't understand what I'm doing here
Answer:
8z - 1
Step-by-step explanation:
Given
3 + 4(2z - 1) ← multiply each term in the parenthesis by 4
= 3 + 8z - 4 ← collect like terms
= 8z - 1