If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Answer: b
Step-by-step explanation:
Hey there Mejia021274,
1) Independent systems have exactly one solution:
x + y = 1
x - y = 3
x = 2, y = -1
2) Inconsistent systems have no solutions :
5x + y = 6
5x + y = 10
There is no solution as 5x + y cannot be equal to 6 and 10
3) Consistent systems have a lot of solutions:
x+y = 5
<span>2x+2y = 10 </span>
<span>A few solutions to this system are (1,4), (2,3), (3,2), (4,1), (5,0), and so on.
</span>
Hope this helps :))
~Top
Answer:
See below
Step-by-step explanation:
For a parallelogram m < A = m < C so:-
75 + 5x = 87 + 3x
2x = 12
x = 6
and m< A = 75 + 30 = 105
and m < C = 87 + 18 = 105
Now if the other 2 angles are = 75 degrees( that is the same side angles add up to 180 degrees) we have proved that it is a parallelogram.
m < B = m < D
111 - 6x = 39 + 6x
-12x = -72
x = 6
m < B = 111 - 36 = 75 and m < D = 39 + 36 = 75
So this has been proved.