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3 years ago

Would a teacher calculating your grade need to have exact or estimated values?

Mathematics

1 answer:

Darina [25.2K]3 years ago

4 0

Answer:

It depends on what teacher you have.

Step-by-step explanation:

Both are very important.

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This is a picture of a cube and the net for the cube.

Nataliya [291]

Answer:

1196 mm^2

Step-by-step explanation:

That's really well described. All in all you have 6 squares all laid out flat. Each square has a side of 14 mm.

The area of 1 square = 14mm * 14mm = 196 mm^2

The area of 6 squares = 6 * 196 mm^2 = 1176 mm^2

3 0

4 years ago

Is this correct<br> 1 problem<br> 15 POINTS

Ne4ueva [31]

After plugging in three numbers for x, its safe to say that the most logical answer would be the last one

5 0

4 years ago

Read 2 more answers

Help please ITS OF TRIGONOMETRY<br>PROVE

Flauer [41]

Answer:

The equation is true.

Step-by-step explanation:

In order to solve this problem, one must envision a right triangle. A diagram used to represent the imagined right triangle is included at the bottom of this explanation. Please note that each side is named with respect to the angle is it across from.

Right angle trigonometry is composed of a sequence of ratios that relate the sides and angles of a right triangle. These ratios are as follows,

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

One is given the following equation,

$\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0$

As per the attached reference image, one can state the following, using the right angle trigonometric ratios,

$sin(A)=\frac{a}{c}\\\\sin(B)=\frac{b}{c}\\\\cos(A)=\frac{b}{c}\\\\cos(B)=\frac{a}{c}$

Substitute these values into the given equation. Then simplify the equation to prove the idenity,

$\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0$

$\frac{\frac{a}{c}+\frac{b}{c}}{\frac{b}{c}+\frac{a}{c}}+\frac{\frac{b}{c}-\frac{a}{c}}{\frac{a}{c}-\frac{b}{c}}=0$

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}$

Remember, any number over itself equals one, this holds true even for fractions with fractions in the numerator (value on top of the fraction bar) and denominator (value under the fraction bar).

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}$

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{-(a-b)}{c}}{\frac{a-b}{c}}$

$1+(-1)=0$

$1-1=0$

$0=0$

7 0

3 years ago

49 Which of the following is a measure

Mariulka [41]

we are ask for measuring of center

there are 3 different measures

mode, when the data value occurs the most frequently

median, is the data value in the middle of a sorted list of data

mean is the average of the numbers

so the answer is A) mean and median

4 0

2 years ago

What is the point-slope form of an equation with the slope of 3/5 that passes through the point (10, –2)?

bekas [8.4K]

Answer to the first question is A. X = 10 and y = -2. Plug it into the equation.
-2 + 2 = 3/5(10 - 10)
0 = 0

Answer to the second question is A. It is going up "rise" by 4. And left "run" by -5

Answer to the third question is A. 2x will represent the slope. 5 will represent the y intercept.

Answer to the fourth question is C.

Answer to the last question is B. y = 5(1) y = 5. y = 5(0) y = 0.

Hope that helps

8 0

4 years ago