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4 years ago

What is the point-slope form of an equation with the slope of 3/5 that passes through the point (10, –2)?

1 answer:

8 0

Answer to the first question is A. X = 10 and y = -2. Plug it into the equation.
-2 + 2 = 3/5(10 - 10)
0 = 0

Answer to the second question is A. It is going up "rise" by 4. And left "run" by -5

Answer to the third question is A. 2x will represent the slope. 5 will represent the y intercept.

Answer to the fourth question is C.

Answer to the last question is B. y = 5(1) y = 5. y = 5(0) y = 0.

Hope that helps

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How is the quotient 8,000÷2,000 different from the quotient 80,000÷200 or 80,000÷20

kenny6666 [7]

8000/2000<80000/200<80000/20

5 0

3 years ago

Write the equation of a line in slope-intercept form that has a slope of -8 and a y-intercept of (0,3).

Pavel [41]

Y=ax+b
3=-8(0)+b
3=0+b
3=b

Y=-8x+3

(I think this is right, but u might want to double check)

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3 years ago

Solve the equation for t^2 +15t=-36.

Mice21 [21]

Answer:

t=−3 or t=−12

Step-by-step explanation:

Step 1: Subtract -36 from both sides.

t2+15t−(−36)=−36−(−36)

t2+15t+36=0

Step 2: Factor left side of equation.

(t+3)(t+12)=0

Step 3: Set factors equal to 0.

t+3=0 or t+12=0

t=−3 or t=−12

7 0

3 years ago

HELP ME it's almost due find the length of the diagonals of rectangle QRST

Westkost [7]

Answer:

11.since diagonal are equal of rectangle

QS=RT

4x+6=6x-4

6+4=6x-4x

2x=10

x=10/2

x=5

now

diagonal :4x+6=4*5+6=26

12.

again

QS=RT

9x+12=11x-10

12+10=11x-9x

2x=22

x=11

now

diagonal=9*11+12=99+12=111

8 0

3 years ago

Suppose that $12,724 is invested at an interest rate of 6.1% per year, compounded continuously. Find the exponential function th

olchik [2.2K]

Answer:

Exponential Function: $A= P* e ^ {0.061t}$

Balance after

t=1 $ 13,524.32

t=2 $ 14,374.99

t=5 $ 17,261.69

t=10 $ 23,417.64

Step-by-step explanation:

Formula used to find amount in the account after time t, given the interest rate is compounded continuously

$A= Pe^r^t$

where: P= principal amount or amount invested

r= interest rate

t= time

A= amount after time t

in our question we are given:

P=$12,724

r= 6.1% or 0.061

$A= 12724 * e ^ (^0^.^0^6^1^)^t$

The above equation is exponential function that describes the amount in the account after time t in years

Now, for t = 1

$A= 12724 * e ^ {0.061 * 1}$

A= $ 13,524.32

t=2

$A= 12724 * e ^ {0.061 * 2}$

A= $ 14,374.99

t= 5

$A= 12724 * e ^ {0.061 * 5}$

A= $ 17,261.69

t=10

$A= 12724 * e ^ {0.061 * 10}$

A= $ 23,417.64

7 0

4 years ago