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2 years ago

Can someone help me with this problem??

Mathematics

1 answer:

Crank2 years ago

4 0

Answer:

V = 33.49

Step-By-Step Explanation:

V = 4/3πr³

V = 4/3×π×2³

V = 4/3×π×8

V = 4/3×25.12

V = 33.49333...

Shortened

V = 33.49

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what is 9z+2=6z-10-z-4 we have to do something called railroad tracks where we put lines down the sides of the equal sign but I

Colt1911 [192]

You want to solve for 'z'.
First combine like terms on either side of the equal sign.

Left side: 9z +2 ----> No like terms, leave alone

Right side: 6z - 10 -z - 4 ----> circle like terms and add
6z -z = 5z
-10 -4 = -14
Now the equation is:
9z + 2 = 5z - 14

Get all the 'z' terms on the left side and all the numbers on right side.
You can move a term to the other side if you flip the sign.

Move 5z to left side, flip the sign to -5z
Move '2' to right side, flip the sign to -2

9z - 5z = -2 -14

Add like terms
4z = -16

Divide by 4 on both sides
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3 years ago

A woman put 580$ into a savings account for one year. The rate of interest on the account is 6.5% how much was the interest

WITCHER [35]

The interest is 37.7$

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3 years ago

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butalik [34]

52.22 - 39.58 = 12.64

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3 years ago

Can someone help me find the hypoteneuse so i can finish this work

MrRa [10]

Answer:

The hypotenuse it opposite from the right angle

Step-by-step explanation:

30.03 I hope this is right

5 0

3 years ago

a 1 =− 3 1 a, start subscript, 1, end subscript, equals, minus, start fraction, 1, divided by, 3, end fraction a i = a i − 1

MrRa [10]

Answer:

$S_{75}=-506.888989761$ X 10^{32}$

Step-by-step explanation:

Given the sequence

$a_1=-\dfrac{1}{3}\\ a_i=a_{i-1}\cdot (-3)$

$a_2=a_{2-1}\cdot (-3)=a_1 \cdot (-3) = -\dfrac{1}{3}\cdot (-3)=1\\a_3=a_{3-1}\cdot (-3)=a_2 \cdot (-3) = 1 \cdot (-3)=-3\\a_4=a_{4-1}\cdot (-3)=a_3 \cdot (-3) = -3 \cdot (-3)=9\\$

Therefore the sequence is:

$-\dfrac{1}{3}, 1, -3, 9, ...$

This is a geometric sequence where the:

First Term, $a_1=-\dfrac{1}{3}$

Common ratio, r =-3

We want to determine the sum of the first 75 terms.

For a geometric sequence, the sum:

$S_n=\dfrac{a_1(1-r^n)}{1-r} \\$

Therefore:

$S_{75}=\dfrac{-\dfrac{1}{3}(1-(-3)^{75})}{1-(-3)} \\\\=\dfrac{-(1-(-3)^{75})}{4*3}\\\\S_{75}=\dfrac{(-3)^{75}-1}{12}\\\\S_{75}=-506.888989761$ X 10^{32}$

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3 years ago