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3 years ago

Solve for x x^2-2x+1=0

Mathematics

1 answer:

Molodets [167]3 years ago

3 0

Answer:

x=1

Step-by-step explanation:

By factoring, you'll compress the equation to (x-1)^2=0

Next take out the square: x-1=0

Now subtract one to the other side to get x! x=1

Hope this helps! :)

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Answer:

The expression is

$.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ C \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{284}&{483}&{410}\\{597}&{551}&{233}{2}}\\\end{array}\right]$

Step-by-step explanation:

From the question we are told that

The number of each items made in the month of January[J] is

$.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ C \ \ \ \ \ \ T\\J = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{144}&{474 }&{274}\\{598}&{572}&{302}\\\end{array}\right]$

The number of each items made in the month of February[F] is

$.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ C \ \ \ \ \ \ T\\J = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{ 424}&{492}&{546}\\{596 }&{530}&{164}\\\end{array}\right]$

Generally given that the production for March of all products at all locations was the average of the January and February production then the number of each items made in the month of March[M] is

$.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ \ \ \ \ \ \ \ C \ \ \ \ \ \ \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{\frac{144 +424}{2}}&{\frac{474 +492}{2}}&{\frac{274 +546}{2}}\\{\frac{598 +596}{2}}&{\frac{572 +530}{2}}&{\frac{302+164}{2}}\\\end{array}\right]$

=> $.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ C \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{284}&{483}&{410}\\{597}&{551}&{233}{2}}\\\end{array}\right]$

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3 years ago

Find the value of f(3) for the function. f(3)=-5(x+5)

iogann1982 [59]

Answer:

Step-by-step explanation:

f(3)=-5(x+5)

=5(3) +5

=15+5

f(3) =20

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