It looks like the finals are a triangle assembled by an ensemble. If yes, then each end has area
4 * 3.5 + 3.5^2/4 √3
<h3>The sides are</h3>
- Two reais each 3.5*15
- Two can be each 4*15
Then some all areas = 119 ft
If I got the shape wrong, it's because an equilateral triangle of side 3.5 cannot have height 4.
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Answer:
0.00508368 grams
Explanation:
From the question we are told that the daily allowance for infants and children is 8.00 × 10⁻⁶ mole of copper per kiogram of body weight.
Since this value is given in moles, we have to convert it to mass
Molar mass of a compound = mass in grams / no of moles of the compound.
So, Molar mass of copper = 63.546
No of moles of copper per kg = 8.00 × 10⁻⁶ mole
63.546 = mass/ 8.00 × 10⁻⁶ mole
Cross multiply
Mass of copper per kg body weight = 8.00 × 10⁻⁶ × 63.546
= 0.000508368 grams
Hence, the daily allowance of copper required for infants or children per kg of weight = 0.000508368 grams.
For a 10 kg infant this is calculated as:
If 1 kg per weight of an Infant = 0.000508368grams
10 kg =
We cross multiply
10 kg × 0.000508368 grams
= 0.00508368 grams.
Therefore, the mass of copper required per day for a 10 kg child is 0.00508368 grams
Answer: The answer is <u>C; left pons</u>.
Explanation:
The patient presents with the symptoms that are common with dysarthria-clumsy hand syndrome. This is one of the lacunar stroke syndromes where dysarthria is common. A x-ray or other imaging would reveal lesions in the contralateral pons.
Answer:
fasciae or, the outer connective tissue just under the skin is part of the structural integrity of the muscle, it also allows the muscle to be able to contract and relax. it can also be used to reduce friction of muscular force.In doing so, fasciae provide a supportive and movable wrapping for nerves and blood vessels as they pass through and between muscles.
Answer:
I believe the answer to this question would be agility.
