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Ivenika [448]
3 years ago
8

I need help on this I’ve been stuck on it for a little bit I will give you brainliest if you help me and I will give 5 stars

Mathematics
2 answers:
BARSIC [14]3 years ago
8 0

Answer: 27 degrees

Step-by-step explanation:

y is 63 degrees because they are alternate interior angles. Then, 90-63=27 which is the answer.

WARRIOR [948]3 years ago
7 0

Answer:

27°

Step-by-step explanation:

  • <em>One of the properties of a rhombus is it has 2 perpendicular diagonals.</em>

So each formed triangle is a right triangle.

We can see one of the angles is 63°, so z= 90° - 63°= 27°

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$15 + $32.50 + 8% = $51.30

15 + 32.50 = 47.50

8% × 47.50 = 3.80

47.50 + 3.80 = 51.30
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Is 28 cups greater or less than 14 Pints
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Short answer: NO.

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Explain how you would round the number 33 and 89 estimate their sum
Brrunno [24]
I am assuming that we have to round the numbers to the nearest tens.
When rounding off numbers, if the number is more than half, then you round it up for example, if the number is 15 and you want to round it off, you round it up to 20. But if the number is 14 you round is down to 10

Therefore, 33 would be rounded off to 30 as 3 is less than 5 in the ones place if you get what I mean.

As for 89, you would round it up to 90 as the 9 in the ones place is more than 5.

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Hope this helps!
8 0
3 years ago
Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot
Andrews [41]

Answer:

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Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

\frac{dm}{dt} = -\frac{t}{\tau}

Where:

m - Current mass of the isotope, measured in kilograms.

t - Time, measured in days.

\tau - Time constant, measured in days.

The solution of the differential equation is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}

\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }

The half-life of a isotope (t_{1/2}) as a function of time constant is:

t_{1/2} = \tau \cdot \ln2

t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2

The half-life difference between isotope B and isotope A is:

\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|

If \frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9, t_{A} = 33\,days and t_{B} = 43\,days, the difference in the half-lives of the isotopes is:

\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|

\Delta t_{1/2} \approx 65.788\,days

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4 0
3 years ago
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Declan draws triangle WXY. He then constructs a perpendicular bisector from vertex W that intersects side XY at point Z. What ca
Ganezh [65]

Answer:

YZ = XZ

Step-by-step explanation:

Perpendicular Bisector:

A perpendicular bisector of a line segment 'l' is a line that is perpendicular to the line segment 'l' and cuts the line segment 'l' into two equal parts.

Given:

1. A triangle WXY.

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a. Z is the midpoint of the line segment XY because point Z lies on the perpendicular bisector of XY.

b. Hence, XZ = YZ.

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3 years ago
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