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Dovator [93]
3 years ago
7

I'm suppose to factor these given, how should I do it?

Mathematics
1 answer:
Sauron [17]3 years ago
6 0
(3x+7)(x-1)=0

3x+7=0

x= -7/3

x-1=0

x=1
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Alex_Xolod [135]

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36

Step-by-step explanation:

12 x 6 = 72 / 2 = 36 because the area of a triangle is base times height divided by 2

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If a bill totals 123.85 with 5% tax and 18% tip what is the total bill
lianna [129]

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Step-by-step explanation:

123.85 x 0.05 = $6.19

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The diagram shows the first four patterns of a sequence.
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A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt
Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

  • v_i=20\sqrt{3}\text{ m/s}
  • a=-9.8\:\mathrm{m/s^2}
  • \Delta y =50\text{ m}

Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

3 0
3 years ago
Help find domain and range
kolezko [41]

Answer:

d: 4 r:5

Step-by-step explanation:

for domain the x coordinates doesn't go over -2 on the left or 2 on the right so if u add the units of the space in between it's 4 since 2- (-2)=4

for the range, the y coordinates never goes over 3 or -2 so range is 5 is u add the units in between

I hope that makes sense!

4 0
2 years ago
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