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2 years ago

PLEASE HELP ASAP, WILL MARK BRAINLIEST

Mathematics

1 answer:

Dahasolnce [82]2 years ago

4 0

Answer:

number 1. C^2 if C>0 number 2. Q^-5 if Q<0. number 3. G^3 if G>0.

number 4. P^-3 if P<0

Step-by-step explanation:

hope this helps .-.

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Slope 1/3 passing through the points (-3,-4)

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Answer:

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Step-by-step explanation:

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2 years ago

What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Ipatiy [6.2K]

Answer:

$x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}$

Step-by-step explanation:

$2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c = - 3 \\\\x = \frac{-b^2\ \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\$

$x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}$

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